As X approaches infinity it approaches close as you like to 0.
so, sin(-1/2)
The limit of cos2(x)/x as x approaches 0 does not exist. As x approaches 0 from the left, the limit is negative infinity. As x approaches 0 from the right, the limit is positive infinity. These two values would have to be equal for a limit to exist.
limit x tends to infinitive ((e^x)-1)/(x)
The sequence sqrt(x)*sin(x) does not converge.
1
The limit does not exist.
The limit of cos2(x)/x as x approaches 0 does not exist. As x approaches 0 from the left, the limit is negative infinity. As x approaches 0 from the right, the limit is positive infinity. These two values would have to be equal for a limit to exist.
limit x tends to infinitive ((e^x)-1)/(x)
What is the limit as x approaches infinity of the square root of x? Ans: As x approaches infinity, root x approaches infinity - because rootx increases as x does.
The sequence sqrt(x)*sin(x) does not converge.
The limit does not exist.
1
It is undefined. In infinities and infinitessimals we use limits, so we see trends as we approach a limit. However this gives different answers, The limit as A approaches infinity of A x 0 is 0. But the limit as B approaches zero of infinty x B is infinite. To be well-defined both of these answers need to be the same.
When the limit as the function approaches from the left, doesn't equal the limit as the function approaches from the right. For example, let's look at the function 1/x as x approaches 0. As it approaches 0 from the left, it travels towards negative infinity. As it approaches 0 from the right, it travels towards positive infinity. Therefore, the limit of the function as it approaches 0 does not exist.
When the limit of x approaches 0 x approaches the value of x approaches infinity.
Anything to the power of 1 is that same something, so infinity to the power of 1 is infinity. Keep in mind that infinity is a conceptual thing, often expressed as a limit as something approaches a boundary condition of the domain of a function. Without thinking of limits, infinity squared is still infinity, so the normal rules of math would seem to not apply.
The limit is 0.
The "value" of the function at x = 2 is (x+2)/(x-2) so the answer is plus or minus infinity depending on whether x approaches 2 from >2 or <2, respectively.