Q: What is the magnitude force of 2 opposite charges?

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The force is proportional to the product of the two charges.If each charge is doubled, the force increases by a factor of 2 x 2 = 4 .

Actually you answer itself is wrong. You can only find the magnitude of force, not the magnitude in force. You can find the magnitude of force by s = (1/2)*a*t^2

Well you mean Coulomb's law, the equivalent of Newton's law for electrostatic?From Wikipedia:The magnitude of the electrostatic force between two point electric charges is directly proportional to the product of the magnitudes of each of the charges and inversely proportional to the square of the total distance between the two charges.

Since, F = 9 x 109 q1q2/r2 provided force between two charges = 1NWhen the magnitude of each charge is double then F' = 9 x 109 (2q1)(2q2)/(2r)2 = FThe force on the charge will remain unchanged.

I'm not sure what this question really means - should it be more like "what two things affect the force between two electric charges?" If this is correct then the answer is probably: 1. The amount of charges. 2. The distance between the charges.

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Yes, electrostatic force obeys Newton's third law; equal and opposite. Example 1: the electrostatic force on a single Na+ due to a single Cl- in a crystal of NaCl is the same magnitude but opposite in direction. Example 2: the electrostatic force on a single Na+ due to a single SO4^2- in a solution of Na2SO4 is the same magnitude as the force on the SO4^2- but in the opposite direction.

The force is proportional to the product of the two charges.If each charge is doubled, the force increases by a factor of 2 x 2 = 4 .

Actually you answer itself is wrong. You can only find the magnitude of force, not the magnitude in force. You can find the magnitude of force by s = (1/2)*a*t^2

Electrical force b/w two charges is given by Coulomb's law. It states that the force 'F' b/w two charges 'q1' & 'q2' separated by a distance 'r' is directly propotional to the product of magnitude of two charges & inversely propotional to square of distance b/w them i.e; F ¤ q1q2/r^2 => F = Kq1q2/r^2 where K = 1/4 pi epsilon nought = 9 *10^9 N m^2/C^2 is called dielectric constant of the medium and epsilon nought =8.854*10^-12 C^2/N m^2 is called absolute permitivity of free space. If the charges are in medium, then epsilon nought is replaced by epsilon.

Well you mean Coulomb's law, the equivalent of Newton's law for electrostatic?From Wikipedia:The magnitude of the electrostatic force between two point electric charges is directly proportional to the product of the magnitudes of each of the charges and inversely proportional to the square of the total distance between the two charges.

They are equal in magnitude but opposite in charge.

A couple: 2 parallel forces equal in magnitude, but opposite in direction separated by a distance.

Since, F = 9 x 109 q1q2/r2 provided force between two charges = 1NWhen the magnitude of each charge is double then F' = 9 x 109 (2q1)(2q2)/(2r)2 = FThe force on the charge will remain unchanged.

I'm not sure what this question really means - should it be more like "what two things affect the force between two electric charges?" If this is correct then the answer is probably: 1. The amount of charges. 2. The distance between the charges.

Hello, some error in the words. Electric "force" not electric charge. A/s we increase the distance between the charges ./2 times then force between them will be halved.

Magnitude and direction.

1. Magnitude 2. Direction 3. Application of force 4. Line of force