Since, F = 9 x 109 q1q2/r2 provided force between two charges = 1N
When the magnitude of each charge is double then F' = 9 x 109 (2q1)(2q2)/(2r)2 = F
The force on the charge will remain unchanged.
Whatever be the magnitude of charge, two charges will always exert equal force on each other. As force depends on the product of magnitude of charges, it will increase if magnitude is doubled but will remain same for both the charges.
The force is proportional to the product of the two charges.If each charge is doubled, the force increases by a factor of 2 x 2 = 4 .
That depends on where the charges are, and the magnitude of the charges. In general, you must calculate the vector for the force due to each individual charge, then add all the vectors together.
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
The magnitude of the test charge must be small enough so that it does not disturb the distribution of the charges whose electric field we wish to measure otherwise the measured field will be different from the actual field.
I dont know haha you tell me.
Whatever be the magnitude of charge, two charges will always exert equal force on each other. As force depends on the product of magnitude of charges, it will increase if magnitude is doubled but will remain same for both the charges.
The force is proportional to the product of the two charges.If each charge is doubled, the force increases by a factor of 2 x 2 = 4 .
They are equal in magnitude but opposite in charge.
Yes. The magnitude of electrical charge on a proton is the same as the magnitude of electrical charge on an electron. The charge on a proton is positive and the charge on an electron is neutral, so that a pair containing one of each of them has no net electrical charge.
That depends on where the charges are, and the magnitude of the charges. In general, you must calculate the vector for the force due to each individual charge, then add all the vectors together.
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
Because the number of positive charges (protons) equals the number of negative charges (electrons), all of which have the same magnitude. Strictly, you mean no NET charge. Clearly it has charges.
Charge is never created or destroyed, only separated and moved from place to place.
The electric charges of the proton and electron are equal in magnitude (size, strength), and opposite in sign.
Yes. A proton has the same magnitude of charge as an electron, but the charge is of the opposite sign.