The magnitude of the resultant force in the case of the concurrent forces in equilibrium.
That the sum of their resolutions in any set of orthonormal directions is zero.
They have equal magnitudes and opposite directions.
First condition for equilibrium. Insofar as linear motion is concerned, a body is in equilibrium if there is no resultant force acting upon it, that is if the vector sum of all the forces is zero. This condition is satisfied if the vector polygon representing all the external forces acting on the body is a closed figure.Equilibrant of a Set of Forces: This is defined as that single force that must be applied to keep a body in equilibrium when it is under the action of other forces. This equilibrant (sometimes called anti-resultant) must be equal in magnitude and opposite in direction to the resultant of the applied forces.http://blog.cencophysics.com/2009/08/composition-resolution-concurrent-forces-vector-methods/
The magnitude of the resultant can be anything between 5N and 15N.
All of the forces together balance out. The resultant of the forces is therefore nil. That applies to all equilibrium.
The direction will change; the magnitude of the resultant force will be less.
The magnitude of the resultant force in the case of the concurrent forces in equilibrium.
They have equal magnitudes and opposite directions.
First condition for equilibrium. Insofar as linear motion is concerned, a body is in equilibrium if there is no resultant force acting upon it, that is if the vector sum of all the forces is zero. This condition is satisfied if the vector polygon representing all the external forces acting on the body is a closed figure.Equilibrant of a Set of Forces: This is defined as that single force that must be applied to keep a body in equilibrium when it is under the action of other forces. This equilibrant (sometimes called anti-resultant) must be equal in magnitude and opposite in direction to the resultant of the applied forces.http://blog.cencophysics.com/2009/08/composition-resolution-concurrent-forces-vector-methods/
If suppose they are not coplanar then resultant of any two cannot cancel the third one and so equilibrium cannot be maintained. Same way as the forces are not concurrent then the same balancing of the resultant by the third one will not be possible.
The first condition of equilibrium can be applied on concurrent forces that are equal in magnitude, since these produce translational equilibrium. But if the forces are equal in magnitude but are non concurrent then even first condition of equilibrium is satisfied but torque is produced which does not maintain rotational equilibrium. Hence for complete equilibrium that is, both translational and rotational , both the conditions should be satisfied.
the resultant magnitude is 2 times the magnitude of F as the two forces are equal, Resultant R= F + F = 2F and the magnitude of 2F is 2F.
All the concurrent forces acting at a point can be represented by a polygon's sides closing with the resultant force equal in magnitude and opposite in direction.
no, if forces have magnitude gr8er than zero. u can check it in topic vector operation, resultant of 2 forces.
The resultant is a trigonometric function, usually using the Law of Cosines in two dimensional solution by vector resolution, of two or more known forces while equilibrant is equal in magnitude to the resultant, it is in the opposite direction because it balances the resultant.Therefore, the equilibrant is the negative of the resultant.
In any situation in which an object doesn't move, it is in equilibrium.
The force is said to be "equilibrant" when acting with other forces it would keep the body at rest ie in equilibrium. Hence equilibrant would be equal in magnitude but opposite in direction to the resultant of all the forces acting on the body.
All of the forces together balance out. The resultant of the forces is therefore nil. That applies to all equilibrium.