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What is the resultant force on system of force 2N and 8N?
The resultant force on the system of forces 2N and 8N acting in the same direction is 10N (2N + 8N).
How can you Calculate the magnitude and direction of the resultant force of an object which is acted on by a force of 4.0N and a force of 10N that are in the same direction?
Add the resultant vectors 4 + 10 (and as they are in the same direction there will be no sine or cosine factors to worry about).Answer: 14N in the direction of the forces
What is the maximum resultant possible when adding a 2 Newton force to a 8 Newton force?
10N if both forces are in the same direction.
If the forces are balanced what is the resulting acceleration?
No. If 2 equal forces are acting on an object in opposite directions it will not accelerate. 10N ->(OBJECT)<-10N = No acceleration. 10N <-(OBJECT)->10N = No acceleration.
What is the maximum net force possible of two forces with a magnitude of 25N and 15N?
Depending on the angle between them, those two forces can combine to producea resultant anywhere between 10N and 40N. The maximum of 40N occurs whenboth forces act in exactly the same direction.
What is the resultant force on system of force 2N and 8N?
The resultant force on the system of forces 2N and 8N acting in the same direction is 10N (2N + 8N).
How can you Calculate the magnitude and direction of the resultant force of an object which is acted on by a force of 4.0N and a force of 10N that are in the same direction?
Add the resultant vectors 4 + 10 (and as they are in the same direction there will be no sine or cosine factors to worry about).Answer: 14N in the direction of the forces
What is the maximum resultant possible when adding a 2 Newton force to a 8 Newton force?
10N if both forces are in the same direction.
If a book is pushed by 10N and the friction is 8N what is the resultant force?
In fact, there is an infinite number of answers because force is a vector, meaning that it has a magnitude and an orientation. For example, if someone pushes horizontaly onto the book (10N) and the friction is 8N in the opposite direction, the resultant force is 2N. But if the book is pushed at an angle, the resultant force changes.
If diagram of force is 3n 10n 8n 5n which direction will the object move?
The object will move in the direction of the net force, which is the vector sum of all the forces. In this case, the net force would be 3N + 10N + 8N + 5N = 26N. So, the object will move in the direction of the resultant force, which is 26N.
If the forces are balanced what is the resulting acceleration?
No. If 2 equal forces are acting on an object in opposite directions it will not accelerate. 10N ->(OBJECT)<-10N = No acceleration. 10N <-(OBJECT)->10N = No acceleration.
What is the maximum net force possible of two forces with a magnitude of 25N and 15N?
Depending on the angle between them, those two forces can combine to producea resultant anywhere between 10N and 40N. The maximum of 40N occurs whenboth forces act in exactly the same direction.
How are net forces and balanced forces not always alike?
Balanced forces means the net force is zero, but net force can also be positive or negative numbers. If I pull a block with a force of 10N to the right, and you pull it with a force of 10N to the left, the net force on the block is zero, thus balanced forces. If I start to pull with a force of 20N to the right, but you still pull 10N to the left, the net force on the block is 10N to the right, thus causing acceleration of the block to the right, thus unbalanced forces
If a box is being pushed 20N to the left and 10N to the right what is the net force.?
The net force is the difference between the two forces. In this case, the net force is 20N (left force) - 10N (right force) = 10N to the left.
Find the magnitude and direction of the resultant if forces of 10N 12N 6N act on a particle in the direction due west S30E N30E respectively?
Sorry we can't sketch a pictorial of the question. 1). The 10N force is all in the -x direction. 2). The 12N force has a component in the +x direction = 12sin(30)and a component in the -y direction = 12cos(30) 3). The 6N force has a component in the +x direction = 6sin(30)and a component in the +y direction = 6cos(30) The horizontal components are: -10 + 12sin(30) + 6sin(30) = -10 + 18sin(30) = -10 + 9 = -1N The vertical components are: -12cos(30) + 6cos(30) = -6cos(30) = -(6/2)sqrt(3) = -3sqrt(3) = -5.19615N The (magnitude)2 of the resultant = (-1)2 + (3sqrt(3))2 = 1 + 27 = 28The magnitude of the resultant = sqrt(28) = 5.2915N (rounded) The direction of the resultant = S [tan-1(1/5.19615)] W = S30W (just a little bit rounded)
What is the resultant magnitude of 6N force acting at right angle to a 8N force?
The magnitude of the resultant force is found using the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides. In this case, the resultant force is √(6^2 + 8^2) = √(36 + 64) = √100 = 10N.
What is the unbalanced force on an object when two equal and opposite forces of 3 N act on an object?
When two forces acting on an object are not equal in size, we say that they are unbalanced forces. a stationary object starts to move in the direction of the resultant force. ... a moving object changes speed and/or direction in the direction of the resultant force.
