To find the mass of 0.55 moles of C6H6 (benzene), first calculate its molar mass. The molar mass of C6H6 is approximately 78.11 g/mol (6 carbon atoms at about 12.01 g/mol each and 6 hydrogen atoms at about 1.01 g/mol each). Multiplying the number of moles by the molar mass, the mass of 0.55 moles of C6H6 is about 42.96 grams.
The molar mass of benzene is 78 g.
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
Each molecule of C6H6 contains 6 carbon atoms, so when 1 mole of C6H6 decomposes, 6 moles of carbon atoms are obtained. Therefore, in a 1.68 mole sample of C6H6, 6 × 1.68 = 10.08 moles of carbon atoms can be obtained from the decomposition.
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
A mole of oxygen atoms has a mass of approximately 16 grams. A mole of O2 has a mass of approximately 32 grams. A mole is 6.02 x 1023 particles and as such a mole of oxygen atoms has only half the mass of a mole of oxygen molecules.
The molar mass of benzene (C6H6) is approximately 78 grams per mole.
Benzene has a molar mass of approximately 78 grams per mole. This is calculated by adding together the molar mass of each carbon atom (12 grams per mole) and each hydrogen atom (1 gram per mole) in the chemical formula C6H6.
First, calculate the moles of each component: moles of HCl = 72.0 g / molar mass of HCl and moles of C6H6 = 468 g / molar mass of C6H6. Then, calculate the total moles in the solution by adding the moles of each component. Finally, calculate the mole fraction of benzene by dividing the moles of C6H6 by the total moles in the solution.
Benzene has a chemical formula of C6H6 This has a molar mass of 78. So one mole has a mass of 78 grams
Molar mass C6H6 = 12.0x6 + 1.00x6 = 72 + 6 = 78 g/mole12.7 moles x 78 g/mole = 990.6 grams = 991 g (to 3 significant figures)
The molar mass of benzene is 78 g.
The molar mass of C2H6 is 30 {(12*2)+(1*6)}. The number of moles(n)=mass/molar mass n=9.3 g/ 30 g mol-1 =0.31 mol. The number of molecules of C2H6 =n* Avogadro number(L)= 0.31*6.022*1023= 1.86682*1023 The no. of atoms in one mole of C2H6=8 The no. of atoms in 0.31 moles of C2H6=8*1.86682*1023 =14.93456*1023 =1.49*1024
The molar mass of benzene (C6H6) is approximately 78 grams per mole. This is calculated by adding up the atomic masses of carbon (12.01 g/mol) and hydrogen (1.01 g/mol) in the compound.
1 mole of C6H6 produces 6 moles of CO2 during combustion. Therefore, 0.4000 moles of CO2 would require (0.4000 moles CO2) / (6 moles C6H6 per mole CO2) = 0.0667 moles of C6H6 to be completely combusted.
The molar mass of benzene (C6H6) is 78.11 grams per mole. The molar mass of toluene is 92.14 grams per mole. Mole fraction of a solute equals moles of solute divided by the moles of solute plus the moles of solvent. .5 of each is the mole fraction.
To calculate the number of moles in 17.2 g of benzene, divide the given mass by the molar mass of benzene. The molar mass of benzene (C6H6) is approximately 78.11 g/mol. Therefore, 17.2 g ÷ 78.11 g/mol ≈ 0.22 moles of benzene.
Each molecule of C6H6 contains 6 carbon atoms, so when 1 mole of C6H6 decomposes, 6 moles of carbon atoms are obtained. Therefore, in a 1.68 mole sample of C6H6, 6 × 1.68 = 10.08 moles of carbon atoms can be obtained from the decomposition.