You can find the mass of one mole of each of the individual elements by looking at the mass numbers.
So, 1 mole of:
N=14g
H=1g
since there are 3 H's the total mass of 1 mole NH3 is 14+3=17g
You then multiply the actual number of moles by the g's per mole:
=> 17x2.11=35.87g
N-14,F-1,Cl-35.5 Mass of 2NH4Cl=2(14+4*1+35.5)g =(2*53.5)g =107g
(2.50 moles NH3) (17.04 grams NH3/moles NH3) = 42.6 grams of NH3
17.04 grams is the molecular weight of ammonia
To calculate the number of moles from grams, you must divide by the substance's molar mass
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2.3456 grams lead (1 mole Pb/207.2 grams) = 0.01132 moles of lead =================
To find the number of moles in 57 grams of Xenon, divide the given mass (in grams) by the molar mass of Xenon. The molar mass of Xenon is 131.3 grams/mol. Therefore, 57 grams of Xenon is equal to 0.434 moles (57/131.3).
The atomic weight of manganese is 54,938 044.Mass in grams of 2,5 moles: 54,938 044 x 2,5 = 137,34511 g
To calculate the number of moles from grams, you must divide by the substance's molar mass
You divide the 6.073 by 6.022x1023 (avagadros number) to get the moles, then multiply by molecular mass (18) to get mass in grams
Multiply the molar mass value ( 32.0 grams per mole O2) by the number of moles (1.5 mole) to get its mass (48.0 grams for 1.5 mole O2)
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For this you need the atomic mass of Si. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.2.61 grams Si / (28.1 grams) = .0963 moles Si
2.3456 grams lead (1 mole Pb/207.2 grams) = 0.01132 moles of lead =================
52.1grams. moles = mass (in grams)/RMM (relative molecular mass) 1.3 moles = mass (in grams)/ 40.078 mass = 40.078 x 1.3 = 52.1grams
# of moles = grams of substance / molar mass of substance molar mass of Barium =137.33 grams/mole #moles of Barium = 22.3 grams/ 137.33 grams/mole = 0.162382582 moles
For this you need the atomic (molecular) mass of CH4O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CH4O=32.0 grams.998 grams CH4O / (32.0 grams) =.0312 moles CH4O
The molar mass of Al2O3 is 101.96 g/mol. To calculate the mass of 9.27 moles of Al2O3, you would multiply the moles by the molar mass: 9.27 mol x 101.96 g/mol = 945.442 g. So, the mass of 9.27 moles of Al2O3 is approximately 945.442 grams.
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g
number of moles = mass of the material/molar mass