0
What else can I help you with?
How many grams of oxygen are required to burn 4.8 mol of butane?
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
How many moles of carbon are atoms are in 1.574 g of Novocain C13H21N2O2Cl?
The molecular weight of Novocaine/Procaine (C12H21N2O2Cl) is 236.3 grams per mole. Each molecule of Novocaine contains 12 moles of carbon (C). 1.574 grams of Novocaine equals .006661 moles. Therefore, .07993 moles of C are to found in this sample size.
How many moles of carbon are in 10.5g of ibuprofen?
The formula of Ibuprofen is: C13H18O2 The molar mass is: 13x 12.01= 156.13 g/mol of C 18x1.008 = 18.144 g/mol of H 2x16.00 = 32.0 g/mol of O Total: 206 g/mol of ibuprofen
13 grams per liter equals how many grams per deciliter?
1.3 grams/deciliter, since there is 10 dl in 1 liter!
How many atoms are in 9.00 grams of carbon 13?
There are approximately 6.022 x 10^23 atoms in 12 grams of carbon-12 (Avogadro's number). Since carbon-13 has one more neutron, it will have a slightly lower number of atoms than carbon-12 per unit mass. Therefore, there will be slightly fewer atoms in 9.00 grams of carbon-13 compared to carbon-12, but the difference is negligible.
How many moles of atoms are in 8 grams of carbon 13?
0,666 moles
How many grams of oxygen are required to burn 4.8 mol of butane?
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
How many ounce in 13 grams?
13 ounces = 368.54 grams. The formula to convert 13 ounces to grams 13 oz* 28.34952313 g 1 oz = 368.5438006 g
How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
How many moles is 3 grams of carbon?
By definition, one mole would be the same as the atomic mass. You take the number of moles and multiply it by the atomic mass. So if you have just 1 mole, the number of grams will be the atomic mass. Carbon's atomic mass is 12.011 grams.
How many moles of atoms are in 9.00g of carbon 13?
Formal set up. ( Avogadro's number appears as form of 1 here ) 9.00 grams 13C (1 mole 13C/13.00 grams)(6.022 X 1023/1 mole 13C)(1 mole atoms 13C/6.022 X 1023) = 0.692 mole of 13C atoms ====================
How many moles are in 13 g of NaCl?
13(g) / 58.5(g/mol) = 0.22 mol NaCl
How many electrons are in 9.00 grams of carbon 13?
To find the number of electrons in 9.00 grams of carbon-13, we first need to determine the number of moles of carbon-13 in 9.00 grams using its molar mass. Then, we multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of atoms. Since carbon-13 has 6 electrons, the total number of electrons would be 6 times the number of atoms.
Find the mass in grams of 5.20 10 molecules of F2?
To find the mass of 5.20 x 10^22 molecules of F2, first calculate the molar mass of F2 (38.00 g/mol). Then, convert the number of molecules to moles by dividing by Avogadro's number (6.022 x 10^23). Finally, multiply the moles by the molar mass to get the mass in grams, which is approximately 3.1 grams.
How many moles are present in 500.00 g of H2O?
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O= 18.0 grams500.0 grams H2O / (18.0 grams) = 27.8 moles H2O
How much is 13 oz in grams?
13 ounces = 368.54 grams. The formula to convert 13 oz to grams: 13 oz* 28.34952313 g 1 oz = 368.5438006 g
How many grams of oxygen are needed for the complete combustion of the butane in the lighter?
The variables for the formula are incomplete. You would need to know how many grams of butane are put out by the lighter. The molecular weight of butane is 58.12 g/mol, which is also needed to complete the formula.
