To determine the number of moles of carbon in 11.5 g of ibuprofen, you first need to calculate the molar mass of ibuprofen. Since ibuprofen has a molar mass of 206.28 g/mol and carbon accounts for 74.08 g/mol within that total, you would divide 11.5 g by 74.08 g/mol to find that there are approximately 0.155 moles of carbon in 11.5 g of ibuprofen.
0.1 moles There is one carbon and two oxygens 1 x 0.1 = 0.1
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles
The balanced chemical equation for the reaction is: C + 2SO2 → CS2 + 2O2. From the equation, 1 mole of carbon produces 1 mole of CS2. Therefore, if 5.9 moles of carbon react, 5.9 moles of CS2 are produced.
The number of moles of carbon in 11,5 g of ibuprofen is 0,725.
To determine the number of moles of ibuprofen containing 7.4x10^25 atoms of Carbon, we first find the number of moles present in 1 mole of ibuprofen. Ibuprofen's molecular formula is C13H18O2, so 1 mole of ibuprofen contains 13 moles of Carbon atoms. To find the moles of ibuprofen containing 7.4x10^25 Carbon atoms, we divide 7.4x10^25 by 13.
To determine the number of moles of carbon in 11.5 g of ibuprofen, you first need to calculate the molar mass of ibuprofen. Since ibuprofen has a molar mass of 206.28 g/mol and carbon accounts for 74.08 g/mol within that total, you would divide 11.5 g by 74.08 g/mol to find that there are approximately 0.155 moles of carbon in 11.5 g of ibuprofen.
To find the grams of Ibuprofen, you first need to know its molar mass, which is 206.28 g/mol. Then, you can calculate the grams by multiplying the number of moles (0.525 mol) by the molar mass (206.28 g/mol), which gives you approximately 108.2 grams of Ibuprofen.
0.1 moles There is one carbon and two oxygens 1 x 0.1 = 0.1
There are twice as many oxygen atoms as carbon atoms in carbon dioxide, so 100.0 moles of carbon dioxide would contain 200.0 moles of oxygen atoms.
211g of carbon dioxide are equal to 4,794 moles.
19
1 gram carbon (1 mole C/12.01 grams) = 0.08 moles carbon ===============
85.636 grams carbon (1 mole C/12.01 grams) = 7.1304 moles of carbon ---------------------------------
That is 3.704 ounces.
105g = 3.7oz