The mass of 4.38 liters of oxygen is 6,259 g.
The density of a substance is equal to its mass divided by its volume. To calculate the density of oxygen in this case, we need to divide its mass by its volume. So, the density of 10 liters of oxygen with a mass of 0.014 would be 0.0014 g/mL.
438 grams.
The molar mass of any gas in liters is 22.4 For example The molar mass of O2 and O are both 22.4 since gas is compressible.
To calculate the FiO2 (fraction of inspired oxygen) when mixing 15 liters of oxygen and 15 liters of air, you first determine the total volume of the mixture, which is 30 liters. Air is approximately 21% oxygen, so 15 liters of air contains about 3.15 liters of oxygen. Adding the 15 liters of pure oxygen gives a total of 18.15 liters of oxygen in 30 liters of gas. Therefore, the FiO2 is 18.15 liters of oxygen divided by 30 liters total, resulting in an FiO2 of approximately 60.5%.
Take example that we r providing 2L/min of oxygen to a ptHuman lungs are 2 liters in volume by average. So...Average breath rate is 12 breaths per minute.In one minute the patient would take in 24 liters of air. You are supplying 2 liters of pure oxygen + 4.8 liters from air (20% of the 24 liters (Percent oxygen in dry air)) = 6.8 liters of Oxygen per minute.6.8 liters oxygen / 24 liters intake = 28.3% Oxygen
Convert 40% oxygen to liters
Offcurse mass is calculated in gram. Liters is the unit for volume
If a substance is 28% oxygen, it means that 28% of the total substance is oxygen. To find the amount of oxygen in liters, you would need to know the total volume of the substance. Without this information, it is not possible to determine the exact amount of oxygen in liters.
No : liters is a unit for volume
To determine how many liters of oxygen represents 40 percent, you need to know the total volume of the mixture. For example, if you have 100 liters of gas, then 40 percent of that would be 40 liters of oxygen. Thus, the specific volume of oxygen depends on the total volume you’re considering.
To find the amount of oxygen required for the combustion of liquid benzene, you would need to balance the combustion reaction equation for benzene. Calculate the moles of benzene from the given mass, then use the stoichiometry of the balanced equation to determine the moles of oxygen required. Finally, convert the moles of oxygen to liters using the ideal gas law.
The volume of one mole of oxygen can be estimated by the ideal gas law. In this case, you will use V = nRT/P, where n is the moles of gas, R is the ideal gas constant, T is the temperature in kelvin, P is the system pressure.