Assuming that the number "9.871023" would or should have been written as "9.87 X 1023" if the typographical resources to do so were available to the questioner:
Avogadro's Number, which is the number of formula units in a mole of any material, is about 6.022 X 1023. The gram formula mass for aluminum oxide is 101.96. Therefore, the mass of the stated number of formula units of aluminum oxide is:
101.96(9.87/6.022) or about 164 grams, to the justified number of significant digits.
CH3(CH2O)n is the formula for polyethylene oxide.
Na2O is sodium oxide. The 2 at the beginning means that there are two formula units of it.
There are 4 atoms of aluminum in 2Al2O3. Each formula unit of Al2O3 contains 2 atoms of aluminum. Therefore, when we have 2 formula units (2Al2O3), we have a total of 4 aluminum atoms.
To determine the number of formula units in 4.89 moles of sodium oxide, you need to first calculate the molar mass of sodium oxide (Na2O). The molar mass of Na2O is 61.98 g/mol. Next, you convert 4.89 moles to grams by multiplying by the molar mass. Finally, divide the mass by the molar mass of Na2O to find the number of formula units, which is approximately 4.34 x 10^23 formula units.
1 formula unit of aluminum sulfate has the formula Al2(SO4)3. So there are 2 atoms of aluminum, 3 atoms of sulfur and 12 atoms of oxygen in 1 formula unit of aluminum sulfate. There are no molecules of aluminum sulfate. They are called formula units.
The formula mass of aluminum oxide (Al2O3) is approximately 102 atomic mass units.
In the chemical formula (4\text{AI}_2\text{O}_3), the "4" indicates that there are four units of aluminum oxide ((\text{AI}_2\text{O}_3)). This means that the compound consists of four molecules of aluminum oxide, which contains a total of eight aluminum atoms and twelve oxygen atoms when considering the subscripts in the formula.
K2O is potassium oxide. Formula mass = 94g32.6 g x 1 FU/94 g = 0.35 formula units
K2O is potassium oxide. Formula mass = 94g32.6 g x 1 FU/94 g = 0.35 formula units
To find the number of formula units of magnesium oxide in 5.68 moles, you first need to determine the formula of magnesium oxide (MgO). Then use Avogadro's number (6.022 x 10^23) to convert moles to formula units. So, in 5.68 moles of MgO, there are approximately 3.43 x 10^24 formula units.
To balance the equation for the reaction of aluminum (Al) with oxygen (O2) to form aluminum oxide (Al2O3), we start with the unbalanced equation: 4Al + 3O2 → 2Al2O3. The coefficient on Al is 4 in this balanced equation, indicating that four aluminum atoms are needed to react with three molecules of oxygen to produce two formula units of aluminum oxide.
CH3(CH2O)n is the formula for polyethylene oxide.
Na2O is sodium oxide. The 2 at the beginning means that there are two formula units of it.
There are 4 atoms of aluminum in 2Al2O3. Each formula unit of Al2O3 contains 2 atoms of aluminum. Therefore, when we have 2 formula units (2Al2O3), we have a total of 4 aluminum atoms.
To determine the number of formula units in 4.89 moles of sodium oxide, you need to first calculate the molar mass of sodium oxide (Na2O). The molar mass of Na2O is 61.98 g/mol. Next, you convert 4.89 moles to grams by multiplying by the molar mass. Finally, divide the mass by the molar mass of Na2O to find the number of formula units, which is approximately 4.34 x 10^23 formula units.
2.159*10^-25
7.2