Assuming that the number "9.871023" would or should have been written as "9.87 X 1023" if the typographical resources to do so were available to the questioner:
Avogadro's Number, which is the number of formula units in a mole of any material, is about 6.022 X 1023. The gram formula mass for aluminum oxide is 101.96. Therefore, the mass of the stated number of formula units of aluminum oxide is:
101.96(9.87/6.022) or about 164 grams, to the justified number of significant digits.
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∙ 2013-12-17 14:55:05K2O is potassium oxide. Formula mass = 94g32.6 g x 1 FU/94 g = 0.35 formula units
K2O is potassium oxide. Formula mass = 94g32.6 g x 1 FU/94 g = 0.35 formula units
5.68 mol MgO x 6.02E23 formula units / 1 mol = 3.42E24 Formula Units
1,8 mol (183,528 g) of aluminium oxide is obtained.
The mass is 991,5 g.
1 formula unit of aluminum sulfate has the formula Al2(SO4)3. So there are 2 atoms of aluminum, 3 atoms of sulfur and 12 atoms of oxygen in 1 formula unit of aluminum sulfate. There are no molecules of aluminum sulfate. They are called formula units.
2.159*10^-25
Na2O is sodium oxide. The 2 at the beginning means that there are two formula units of it.
7.2
One mole of formula units = 6.022 x 1023 formula units.
The chemical equation is Al2(SO4)3 + 3BaCl2 --> 2AlCl3 + 3BaSO4. (I corrected the formulas containing aluminum.)
Aluminum sulfide is Al2S3, which has 3 sulfur atoms per formula unit. 1.10mol means 1.10(6.02x1023), which is 6.62x1023 formula units. Multiple that by 3 to get your sulfur atoms: 6.62x1023(3) = 1.99x1024 sulfur atoms.