Na2O is sodium oxide. The 2 at the beginning means that there are two formula units of it.
4Na+O2= 2Na2O
The reaction of NaI and H2O2 can be represented as follows:-4NaI(aq) +2H2O2(aq)---->2Na2O(s)+ 4HI(l) + O2(g)
4Na + O2 ----> 2Na2O Sodium oxide is formed.
4Na+2O2=2Na2O
4Na + O2 = 2Na2O The reactants are the sodium (Na) and the oxygen (O2) NB The product is Na2O
4Na+O2= 2Na2O
The reaction of NaI and H2O2 can be represented as follows:-4NaI(aq) +2H2O2(aq)---->2Na2O(s)+ 4HI(l) + O2(g)
Sodium + Oxygen = Sodium oxide: 4Na + O2 = 2Na2O
4Na + O2 ----> 2Na2O Sodium oxide is formed.
2Na (s) + O2 (g) ---> 2Na2O (s)
4Na+2O2=2Na2O
4Na + O2 = 2Na2O The reactants are the sodium (Na) and the oxygen (O2) NB The product is Na2O
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4,1,2
Sodium+Oxeygen->Sodium Oxide 4Na+O2->2Na2O
product name
4Na+O2 2Na2O