.0003 cm
.0003 cm
50 ml
0.946 L
The specific gravity of gasoline is approximately 0.701150 kg/min * (m^3/0.70*10^3 kg) * (1000 L /m^3) * (1 min / 60s) = 27 L / s
First off, the density you're meaning must be .70 g/mL. Multiply that by 1000 to get grams per liter (700), then multiply that by the volume (49.2 L). 34440g or 34.44kg or 75.93 pounds.
50 ml is one third of a mug, so 50 l is more likely. 50 ml is one third of a mug, so 50 l is more likely.
The mass flow rate of gasoline from a pump depends on the pump's flow rate and the density of gasoline. It is typically measured in kilograms per second or pounds per hour. The mass flow rate can be calculated by multiplying the volumetric flow rate (in liters per minute or gallons per hour) by the density of gasoline (in kg/L or lb/gal).
To determine the mass of 1.50 L of gasoline, we can use the average density of gasoline, which is approximately 0.75 g/cm³. Therefore, 1.50 L (or 1500 cm³) of gasoline would have a mass of about 1125 grams (1500 cm³ × 0.75 g/cm³). The density of olive oil is approximately 0.92 g/cm³, which means that to find the volume of olive oil that has the same mass, we can use the formula: Volume = Mass / Density. Thus, the volume of olive oil needed is approximately 1228.26 cm³ (1125 g / 0.92 g/cm³).
2003 Yamaha V Star 1100 - Service manualTypeFuel tank capacity 17 L (4.49 gal.)Fuel reserve amount 4.5 L (1.18 gal.)Regular unleaded gasoline
Yes, the volume of gasoline can be calculated using the formula for volume, which is ( V = A \times h ), where ( V ) is volume, ( A ) is the cross-sectional area of the container, and ( h ) is the height of the gasoline in the container. Additionally, if you need to calculate the volume from mass, you can use the formula ( V = \frac{m}{\rho} ), where ( m ) is the mass of the gasoline and ( \rho ) is its density. The density of gasoline typically ranges from about 0.71 to 0.77 kg/L.
To determine the volume of gasoline needed to hold 7.2 kg, we can use the average density of gasoline, which is approximately 0.74 kg/L. By dividing the mass of the gasoline by its density, we find that 7.2 kg ÷ 0.74 kg/L ≈ 9.73 liters. Therefore, you would need a container of at least 10 liters to hold 7.2 kg of gasoline.
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