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What is the mass of water produced when 7.01 g of butane reacts in an excess of oxygen?
Wiki User
∙ 6y ago
The equation is 2C4H10 + 13O2 --> 8CO2 + 10H2O
This means that for each mole of butane there are 5 moles of water produced.
We have 7.01 g of butane = 7.01/58 moles of butane = 0.12 moles.
Thus we will get 5 x 0.12 moles of water, = 5 x 0.12 x 18 g of water
= 10.88 g.
Wiki User
∙ 6y ago
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Increases
Butane burns in oxygen to produce magnesium nitrate an water?
no thats completely stupid. butane reacts with oxygen to produce carbon dioxide and water
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nitrogen oxide
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When butane reacts with oxygen the temperature of the surrounding area?
Increases
When butane reacts with oxygen what does the temperature in the surrounding area do?
It Increases
When butane reacts with oxygen the temperature of the surrounding area .?
Increases
Butane burns in oxygen to produce magnesium nitrate an water?
no thats completely stupid. butane reacts with oxygen to produce carbon dioxide and water
When butane reacts with oxygen the temperature of the surronding area does what?
The temperature, of course increase.
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the temperature should increase not decrease
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Butane reacts with oxygen to form carbon dioxide and water vapor: 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O If there is insufficient oxygen, combustion may be incomplete and some soot (carbon) or carbon monoxide may be produced.
What is a form of oxygen that is produced when nitrogen dioxide reacts with sunlight and oxygen molecules?
nitrogen oxide
