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in every sample of carbon monoxide ,the mass ratio of carbon to oxygen is 3:4
Oxygen. Because , mass of carbon monoxide is 28, whereas that of oxygen is 32.
28g
The mass of 35 gmoles of carbon monoxide ( CO ) is given by : m = ( n ) ( M ) m = ( 35 gmol ) ( 28.00 g / gmol ) = 980 g <----------------
To find the mass of carbon monoxide needed, we need to use the stoichiometric ratio between iron and carbon monoxide. From the balanced equation, we can see that 3 moles of carbon monoxide produce 2 moles of iron. First, calculate the molar mass of iron (Fe), which is 55.85 g/mol. Next, use the molar ratio between iron and carbon monoxide (2:3) to find the moles of carbon monoxide required. Finally, convert the moles of carbon monoxide to grams using its molar mass (28.01 g/mol).
in every sample of carbon monoxide ,the mass ratio of carbon to oxygen is 3:4
Oxygen. Because , mass of carbon monoxide is 28, whereas that of oxygen is 32.
28g
law of multiple proportion
The mass of 35 gmoles of carbon monoxide ( CO ) is given by : m = ( n ) ( M ) m = ( 35 gmol ) ( 28.00 g / gmol ) = 980 g <----------------
0.44g CO
To find the mass of carbon monoxide needed, we need to use the stoichiometric ratio between iron and carbon monoxide. From the balanced equation, we can see that 3 moles of carbon monoxide produce 2 moles of iron. First, calculate the molar mass of iron (Fe), which is 55.85 g/mol. Next, use the molar ratio between iron and carbon monoxide (2:3) to find the moles of carbon monoxide required. Finally, convert the moles of carbon monoxide to grams using its molar mass (28.01 g/mol).
8.20g of carbon monoxide, how many grams of methanol will be produced?
27.2 g
Vehicles
The exhaust releases about 3 percent carbon monoxide
of course we breathe out carbon dioxide not carbon monoxide