Maximum area for a rectangle of a given perimeter is a square so side would be 30m and area 900 sq m
Math behind it:
We have two variables X and Y (width and height)
The perimeter of the rectangle is 120, therefore 2X + 2Y = 120
Now that we have an equation we can get rid of one of the variables like so:
2X + 2Y = 120 => 2Y = 120 - 2X => Y = 60 - X
We want to optimize the area (A), which is X*Y:
A = X * Y => Substitute the Y -> A = X * (60 - X) => A = 60X - X^2
To find the maximum area we'll have to find where the derivative A' zero.
A = 60X - X^2 => Find the derivative -> A' = 60 - 2X
A' = 0 => 60 - 2X = 0 => -2X = -60 => X = 30
Filling in the X to get the Y we get: Y = 60 - X => Y = 60 - 30 => Y = 30
Now that we have the X and the Y we can calculate the maximum area which is:
X * Y => 30 *30 => 900
40 meters.
320 meters squared.
1024
A rectangle 8 metres x 3 metres has a perimeter (distance around) of 22 metres. It has an AREA of 24 square metres.
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
40 meters.
130/4 (4 sides to a rectangle)= 32.5 32.5*32.5=1065.25 square meters (because the largest area of a rectangle is always a ^ ^ square). length width
The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
320 meters squared.
112meters.
100 cm2
No, 12x4 = 48 sq meters. 13x3=39 sq meters.
3 square metres
If it's a rectangle then:- Area = 9*4 = 36 square meters Perimeter = 9+4+9+4 = 26 meters
A square of side 22 has an area of 484. Rectangle 23 x 21 has an area of 483...
1024