2. Two electrons of opposite spin. This is true of all s, p, d, f g.... orbitals, eah can only contain two electrons of opposite spin.
The maximum number of electrons in the p orbitals of each atomic "shell" is 6.
The maximum number of electrons that can occupy one orbital is 2: One with "Up" spin and one with "Down" spin.
Just two, with opposite spin.
2
two
2 electrons
Cesium has 55 electrons in the neutral atom. It has only one outer s-block electron, however. It's outer-most orbital is the 6s1 orbital. If you are looking for the total number of electrons in all of cesium's s-block orbitals, the number is 10. The s-block orbital holds only 2 electrons, and the 1s, 2s, 3s, 4s, and 5s orbitals hold 1 + 2 + 2 + 2 + 2 electrons, or 9 electrons. Add the 1 electron in the 6s orbital and you'll get 10. A link can be found below.
A 5s orbit is real.
Yes, it exists. If you write the orbitals in order of increasing energy, then you get it. The order is:- 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p..................... Here, you get the 3s orbital at the 4th place.
The first orbit only has an S orbital. The S orbital can hold 2 electron. The second orbit has s and p orbitals. The p orbital can hold 8 electrons The third orbit has s, p, and d orbitals. The d orbital hold 10 electrons giving a total of 18. However the 3d orbital has a higher energy level than 4s so the 4s orbital is filled with electrons before you can put electrons in the 3d orbital. The fourth orbital has s,p,d,and f. The f orbital can hold 14 electrons. This gives a total of 32 electrons. However the 4f orbital is higher in energy than the 5s, 5p, and 62 orbitals. Therefore these orbitals must be filled first. The fifth, sixth and seventh orbitals are similar to the fourth.
there are actually 7 orbitals.. the different orbitals are s,p,d,f s has 1, p has 3, d has 5, and f has 7. i hope this helps you..i got this info straight from my chem teacher..
5s orbital
5s orbital-ssmith ;))
If you are filling in the electrons it will be in the 4d orbital. If you are removing electrons the first to come out is in the 5s electrons since transition metals lose 's' electrons before 'd' electrons
Rubidium has one valence electron in the 5s orbital.
3s has a principle quantum number of n=3 5s has a principle quantum number of n=5
Cesium has 55 electrons in the neutral atom. It has only one outer s-block electron, however. It's outer-most orbital is the 6s1 orbital. If you are looking for the total number of electrons in all of cesium's s-block orbitals, the number is 10. The s-block orbital holds only 2 electrons, and the 1s, 2s, 3s, 4s, and 5s orbitals hold 1 + 2 + 2 + 2 + 2 electrons, or 9 electrons. Add the 1 electron in the 6s orbital and you'll get 10. A link can be found below.
Valance electrons are furthest from the nucleus.
A 5s orbit is real.
Yes, it exists. If you write the orbitals in order of increasing energy, then you get it. The order is:- 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p..................... Here, you get the 3s orbital at the 4th place.
in 5s it is filled but in 4d or 4s its half
The first orbit only has an S orbital. The S orbital can hold 2 electron. The second orbit has s and p orbitals. The p orbital can hold 8 electrons The third orbit has s, p, and d orbitals. The d orbital hold 10 electrons giving a total of 18. However the 3d orbital has a higher energy level than 4s so the 4s orbital is filled with electrons before you can put electrons in the 3d orbital. The fourth orbital has s,p,d,and f. The f orbital can hold 14 electrons. This gives a total of 32 electrons. However the 4f orbital is higher in energy than the 5s, 5p, and 62 orbitals. Therefore these orbitals must be filled first. The fifth, sixth and seventh orbitals are similar to the fourth.
The atom always stays in maximum stability.. The orbital with full electrons , no electron or half electrons is maximum stable ... In the case of Cu the electron moves in 3d orbital because in that case the 3d orbital is going to be filled with maximum 10 electrons hence the 4s orbital is going to be filled with half number of electrons - 1 electron ..... So the last electron goes in the 3d orbital except going into 4s orbital..... therefore the electron configuration of Cu is [Ar]3d10 4s1 .....The reason is same for the atom of Silver.....