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3N
The maximum resultant occurs when the forces act in the same direction. Its magnitude is 15 N.
maximum resultant: 45 = a + b minimum resultant: 5 = a - b Solve for a in the first equation then substitute it into the second equation: a = 45 - b 5 = 45 - b -b 5 - 45 = -2b -40 = -2b 20 = b Since we know the value for b we can substitute it into the first equation to find the value for a: 45 = a + 20 45 - 20 = a 25 = a So the magnitude of each of these forces are 20N, 25N.
3n
The net force is calculated using vector addition. For example, if one force acting on an object in a positive direction is 5N, and an opposing force is -3N, the net force would be 5N + (-3N) = 2N.
3N
The maximum resultant occurs when the forces act in the same direction. Its magnitude is 15 N.
maximum resultant: 45 = a + b minimum resultant: 5 = a - b Solve for a in the first equation then substitute it into the second equation: a = 45 - b 5 = 45 - b -b 5 - 45 = -2b -40 = -2b 20 = b Since we know the value for b we can substitute it into the first equation to find the value for a: 45 = a + 20 45 - 20 = a 25 = a So the magnitude of each of these forces are 20N, 25N.
3n
The net force is calculated using vector addition. For example, if one force acting on an object in a positive direction is 5N, and an opposing force is -3N, the net force would be 5N + (-3N) = 2N.
(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!
Let the number be n. Then 3n + 2 = -4 3n = -6 n = -3
what is 3n times 3n-1
The nth term of this sequence is 3n + 4
No. 3n is not a factor of 3n + 7.