4294967295
Hkeje7
2^16-1= 65536
The mantissa holds the bits which represent the number, increasing the number of bytes for the mantissa increases the number of bits for the mantissa and so increases the size of the number which can be accurately held, ie it increases the accuracy of the stored number.
2
2 electrons maximum. 1s2
2 electrons are held closest to the nucleus, after that the maximum per shell is eight.
In reality, it's not. 2,147,483,647 is the largest number that an int type can hold. This is because Java uses a 32-bit signed integer value for ints. Since it's signed, one bit needs to hold the sign value, leaving us 31 bits for storage. 231 = 2,147,483,648, which is the total number of values which can be held in 31 bits. Since we also need to store a zero, our maximum is 2,147,483,647. The total range of data which can be held in an int is [-2,147,483,648 : 2,147,483,647].But, as was said above, this is not the biggest number Java can handle. It also has support for 64-bit long integer types. This type can hold values in the range [-9,223,372,036,854,775,808 : 9,223,372,036,854,775,807].And finally we have the BigInteger class, which can hold infinitely large numbers, limited only by the physical capacity of your storage space (RAM).
The maximum number of electrons that can be held in the third orbit of an atom is 18. This is based on the formula 2n^2, where n is the principal quantum number of the orbit. For the third orbit (n=3), the maximum number of electrons is 2 x 3^2 = 18.
Magazines for the M16 are made in 20 and 30 round capacity.
The maximum number of electrons that can be held in an energy level is given by the 2n^2 rule, where n is the principal quantum number of the energy level. So, for example, the first energy level (n=1) can hold a maximum of 2 electrons, the second energy level (n=2) can hold a maximum of 8 electrons, and so on.
Yes. The copyright on the Maximum Ride series is held by the author, James Patterson.
In the number 321098765, the zero is in the hundred thousands place. Therefore, the value of the zero in this number is 0 multiplied by 100,000, which equals 0. The zero in this position does not change the overall value of the number significantly, as it represents zero hundreds of thousands.