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The area under the velocity time graph of an object is equal to the distance travelled by that object in that time. This is because displacement is the integral of velocity with respect to time so integrating velocity from time A to time B will give the displacement from time A to time B. ( Integrating is the same as calculating the area under the graph)
False
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
Velocity is NOT the slope of the acceleration vs. time graph. Velocity is the area under the acceleration vs. time graph. Velocity is the slope of a position vs. time graph, though. For you Calculus Junkies, v = the integral of acceleration with respect to time.
postion is the area under the slope
The area of a position-time graph does not have a meaning. However, the area under a velocity-time graph is the displacement. Refer to the related link below for an illustration.
Area under velocity versus time graph(between two given instances of time i.e. two points on time axis) gives the displacement of the body( whose graph was plotted) between those two instances i.e. in that time interval. Area under velocity time graph can be found from definite integration if the graph is a curve. Note: Area under velocity versus time graph gives displacement not distance covered by body. Note: Area enclosed between the plotted curve and time axis is taken. For convenience time should be taken in the x-axis.
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
The area under the speed/time graph between two points in time is the distance covered during that time.
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
Distance.
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
The position.
change in velocity
Displacement is the area under the v-t graph.
its the velocity
The area under the velocity time graph of an object is equal to the distance travelled by that object in that time. This is because displacement is the integral of velocity with respect to time so integrating velocity from time A to time B will give the displacement from time A to time B. ( Integrating is the same as calculating the area under the graph)