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Q: What is the measure of an exterior angle of a regular 18-sided polygon to the nearest tenth?

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Each exterior is 360/7 = 51.4 degrees to the nearest tenth

The largest exterior angle measure is 120o. It is the exterior measure of an equilateral triangle (which is a regular polygon).

The exterior angles of any polygon add up to 360 degrees

A regular 10 polygon

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If it's a regular polygon then each exterior angle measures 36 degrees

Providing that it's a regular polygon then each exterior angle will measure 12 degrees.

The measure of the exterior angle of a 11-sided polygon = 360⁰/11 = 32 72/99⁰ = 32 8/11⁰

360/number of sides = exterior angle

The exterior angles add up to 360 degrees

Providing that it is a regular polygon then each exterior angle will measure 12 degrees

Providing that it is a regular 12 sided polygon then each exterior angle measures 30 degrees

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360

360 divided by 120=3the sum of the exterior angle so a polygon is always 360.

A regular polygon will have 360 sides with exterior angles of 181 degrees.

The sum of the exterior angles of a polygon, whatever the measure of each one, is always 360 degrees.

The sum of the exterior angles of ANY polygon is 360 degrees.

The sum of the exterior angles of ANY polygon is 360 degrees.

The exterior angle of a 52-sided polygon is 360/52 = 6.92 degrees, approx.

taco

The sum of the exterior angle of any polygon is 360. So divide that by 8 in this case and each exterior angle has measure 360/8 or 45 degrees.

360 degrees

56

360/number of sides