The efficiency is 80%.
To find the efficiency, 400/500 = 80%.
The machine efficiency is 35 percent (35/100).
94 percent (which is easily calculated, 3760/4000x100).
The efficiency of a machine tells you how much usefull energy it will put out compared to the amount of energy that's put in. The usefull output energy is usually less (never greater) then the input because of energy loss due to frictional heating. For example if 120 joules of energy or work is put into a lifting machine, you might only get out 110 joules of lifting work because 10 joules is lost to heat. The efficiency of the machine is then ; (110/120) x 100% = 91.7% . I think for most practical machines anything above 90% efficient is quite good. (The terms work & energy are used interchangebly here because work is a transfer of energy).
If the input energy is 210 joules and the efficiency of the system is 30%,then the output energy is30% of 210 = (0.3 x 210) = 63 joules.
Joules
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
The machine efficiency is 35 percent (35/100).
.33
.8 or 80%i.e. The output is 80% of the input.
400/500 = 80% efficient
Manufacturing. A machine has a work output of 14ax4 j (joules) and a work in put 7a2x5 j. What is the eficiency of the machine? efficiency in % = work output in joules work input in joules
Efficiency is measured in joules.
94 percent (which is easily calculated, 3760/4000x100).
If the input energy is 210 joules and the efficiency of the system is 30%,then the output energy is30% of 210 = (0.3 x 210) = 63 joules.
The efficiency of a machine tells you how much usefull energy it will put out compared to the amount of energy that's put in. The usefull output energy is usually less (never greater) then the input because of energy loss due to frictional heating. For example if 120 joules of energy or work is put into a lifting machine, you might only get out 110 joules of lifting work because 10 joules is lost to heat. The efficiency of the machine is then ; (110/120) x 100% = 91.7% . I think for most practical machines anything above 90% efficient is quite good. (The terms work & energy are used interchangebly here because work is a transfer of energy).