The Nucleophilic substitution of Halo alkanes
The chemical reactions are:
C2H2 + Br2 = CH2Br2
CH2Br2 + Br2 = CH2Br4
The question is not very specific, so there is more than just one answer, but I'm assuming you are referring to a radical bromination of an alkane (ethane) versus an electrophilic bromination of an alkene (ethene).Br2 in the presence of a radical initiator (such as light or heat) will add to ethane to form 2-bromoethane as the major product in a radical mechanism. This goes through an initiation step (forming 2 bromine radicals), followed by propagation to the alkane (forming a secondary ethyl radical), followed by a termination step. The termination step leading to the product is one where another bromine radical joins with the ethyl radical.In the absence of light or heat, bromine cannot react with an alkane, but it can react as an electrophile with an alkene. In this type of reaction (electrophilic addition to an alkene), the ∏-bond (double bond) on ethene attacks a bromine atom (from Br2) and kicks out a bromide (Br-). The bromine that was just added forms two bonds (one on each carbon of the double bond), giving a three-membered C-Br-C ring called a bromonium ion (since the bromine atom now has a positive charge). The bromide that left before can now attack the backside of the bromonium ion, opening the 3-membered ring, and adding anti to form a dibromoalkane (1,2-dibromoethane in this example). This reaction is stereospecific because in the major product the bromine atoms will always add anti (to the opposite side) on the alkene.
Oxygen is much more dense than ethyne. This is why a test tube full of ethyne would be held upside down so the ethyne doesnt escape into the air.
Ethyne. It's a by product of oil refining and also is made in industrial quantities by the reaction of calcium carbide, CaC2, with water.
The chemical formula of ethyne (acerylene) is C2H2 - two hydrogen atoms.
Ethyne
Yes it does.
ethyne (or acetylene) is non polar
Ethyne is C2H2 2C2H2 + 5O2 ---> 2H2O + 4CO2
Ethyne is acidic in nature and is soluble in aqueous solution of NaOH while ethene does not.
It is the balanced equation for the combustion of acetylene (or ethyne).
convert ethyne into ethane
The question is not very specific, so there is more than just one answer, but I'm assuming you are referring to a radical bromination of an alkane (ethane) versus an electrophilic bromination of an alkene (ethene).Br2 in the presence of a radical initiator (such as light or heat) will add to ethane to form 2-bromoethane as the major product in a radical mechanism. This goes through an initiation step (forming 2 bromine radicals), followed by propagation to the alkane (forming a secondary ethyl radical), followed by a termination step. The termination step leading to the product is one where another bromine radical joins with the ethyl radical.In the absence of light or heat, bromine cannot react with an alkane, but it can react as an electrophile with an alkene. In this type of reaction (electrophilic addition to an alkene), the ∏-bond (double bond) on ethene attacks a bromine atom (from Br2) and kicks out a bromide (Br-). The bromine that was just added forms two bonds (one on each carbon of the double bond), giving a three-membered C-Br-C ring called a bromonium ion (since the bromine atom now has a positive charge). The bromide that left before can now attack the backside of the bromonium ion, opening the 3-membered ring, and adding anti to form a dibromoalkane (1,2-dibromoethane in this example). This reaction is stereospecific because in the major product the bromine atoms will always add anti (to the opposite side) on the alkene.
Oxygen is much more dense than ethyne. This is why a test tube full of ethyne would be held upside down so the ethyne doesnt escape into the air.
By combustion ethyne is transformed in carbon dioxide and water.
Ethyne. It's a by product of oil refining and also is made in industrial quantities by the reaction of calcium carbide, CaC2, with water.
polar
The chemical formula of ethyne (acerylene) is C2H2 - two hydrogen atoms.