It is the balanced equation for the combustion of acetylene (or ethyne).
Ethyne is C2H2 2C2H2 + 5O2 ---> 2H2O + 4CO2
2c2h2+5o2=4co2+2h2o.
there are many possible combinations, as incomplete combustion refers only to the combustion of a fuel whereby not all of a fuel's carbon and hydrogen is converted to carbon dioxide and water, usually other products involve carbon particulates (C) or carbon monoxide (CO) as such two possible equations are:C2H4 + O2 => C2 + 2H20C2H4 + 2O2 => 2CO + 2H2O
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
ΔS is negative and ΔG is negative at low temperatures...
Ethyne is C2H2 2C2H2 + 5O2 ---> 2H2O + 4CO2
2c2h2+5o2=4co2+2h2o.
5O2 + 2C2H2 --> 4CO2 + 2H2O + Qoxygen + acetylene -> carbon dioxide + water + heat-energy
there are many possible combinations, as incomplete combustion refers only to the combustion of a fuel whereby not all of a fuel's carbon and hydrogen is converted to carbon dioxide and water, usually other products involve carbon particulates (C) or carbon monoxide (CO) as such two possible equations are:C2H4 + O2 => C2 + 2H20C2H4 + 2O2 => 2CO + 2H2O
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
ΔS is negative and ΔG is negative at low temperatures...
The C2H2 us being oxidized, electrons stripped away, and the oxygen is being reduced, accepting electrons and in this case, carbon and hydrofen are coming along for the ride.
ΔS is positive and G is negative at all temp.Which of the following is true for the gas phase reaction shown below? 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g), ΔH = -2511 kJΔS is negative and ΔG is negative at low temperatures.
2C2H2(g) + 5O2(g) = 2H2O(g) + 4CO2(g) or, 2 Acetylene molecules + 5 Oxygen molecules = 2 water molecules + 4 Carbon dioxide molecules (+ energy)
2C2H2 + 5O2 ------------->2H2O + 4CO21 mole Of C2H2 = 26.04g, O2 = 32g, H2O = 44.01g, CO2 = 18.01g2moleC2H2 -------------> 4moleCO22x(26.04g) -------------> 4x(18.01g)52.08 g C2H2 ---------> 176.04 g CO230000g C2H2 ---------> ?? =176.04x30000g/52.08 =101405.53 gAnswer=101405.53 gram of CO2
FeedbackThe correct answer is: 2C2H2 + 5O2 4CO2 + 2H2O.
2nacl+2h2o