CH4 + 2O2 -> 2H20 + CO2 There's the balanced equation above. In a balanced equation, all the elements on the reactants side must equal to the elements on the products side. This must hold in order to agree with the law of conservation.
2c2h2 + 5o2 → 4co2 + 2h2o
S8 (s) + 16Cl2 (g) ---> 8SCl4 (?)
You get the reactants, products, and the ratio that the chemicals react in. It also gives information on what processes the chemicals are undergoing, such as oxidation/reduction and acid/base.
The chemical equation is:Mg+ + 2 OH- = Mg(OH)2(s)
Flourine has a charge of -1 and sodium has a charge of +1. Together they are equivalent to 0, so they are already perfectly balanced. An empirical formula is just a way to express the "smallest" balanced ratio. and since you can't get any smaller or more basic than 1 NA and 1 F, your empirical formula is just that: NaF.
KOH(aq)+HC2H3O2(aq)---- H2O(l)+KC2H3O2(aq)
Moles of reactants and products thats wut i put on my test
The chemical equation is a graphic expression of a chemical reaction.
S8 (s) + 16Cl2 (g) ---> 8SCl4 (?)
You get the reactants, products, and the ratio that the chemicals react in. It also gives information on what processes the chemicals are undergoing, such as oxidation/reduction and acid/base.
Moles of one substance compared to moles of the second substance. Ex. moles of reactant A compared to moles pf product F
The chemical equation is:Mg+ + 2 OH- = Mg(OH)2(s)
Flourine has a charge of -1 and sodium has a charge of +1. Together they are equivalent to 0, so they are already perfectly balanced. An empirical formula is just a way to express the "smallest" balanced ratio. and since you can't get any smaller or more basic than 1 NA and 1 F, your empirical formula is just that: NaF.
If you express your answer as a chemical equation with all forms given, you would get: Mg+(g) + e- -> Mg (g)
The chemical equation is:3 NaOH + FeBr3 = 3 NaBr + Fe(OH)3
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KOH(aq)+HC2H3O2(aq)---- H2O(l)+KC2H3O2(aq)
equal