The chemical equation is:
Mg+ + 2 OH- = Mg(OH)2(s)
You get the reactants, products, and the ratio that the chemicals react in. It also gives information on what processes the chemicals are undergoing, such as oxidation/reduction and acid/base.
Yes; you can. In other words, True
S8 (s) + 16Cl2 (g) ---> 8SCl4 (?)
I don't remember all of the mathematical names, but I do remember that you need to balance equations so that both sides will be equal. These are very simple examples but they will show you that balanced equations are equivalentto being equal.Such as: (2+2)=4=(3+1) Both sides equal '4'.Differing equations on opposite sides of the equal sign demonstrate that are differing ways to express a certain figure.Or: (2+6)-(3x1)=5=(2x2)+(4-3) Here both sides equal '5'.(8) - (3) =5= (4) + (1)Hope this helps.
Why don't you express the equation verbally? Q 12 89 doesn't have much meaning.
The chemical equation is a graphic expression of a chemical reaction.
You get the reactants, products, and the ratio that the chemicals react in. It also gives information on what processes the chemicals are undergoing, such as oxidation/reduction and acid/base.
If you express your answer as a chemical equation with all forms given, you would get: Mg+(g) + e- -> Mg (g)
The chemical equation is:3 NaOH + FeBr3 = 3 NaBr + Fe(OH)3
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Yes; you can. In other words, True
Moles of reactants and products thats wut i put on my test
It means you manipulate the equation in such a way that "y" is alone to the left of the equal sign, and everything else (including "x") is to the right.
It means that you manipulate the equation in such a way that "y" appears to the left, and everything else, including "x", to the right, of the equal sign.
The law of mass action states that the rate of a chemical reaction is directly proportional to the concentration of reacting species raised to their respective stoichiometric coefficients. In other words, the rate of a reaction is determined by the concentrations of the reactants involved. The law is used to express the relationship between the concentrations of reactants and products in equilibrium systems.
S8 (s) + 16Cl2 (g) ---> 8SCl4 (?)
equal