Why don't you express the equation verbally? Q 12 89 doesn't have much meaning.
yupe,its efficiency=Q/heating value of fuel
Q<k= he
Q=mc∆T
Acceptance criteria
You just have to use algebra to manipulate the formula that you are used to. Q=mCpΔT, the formula you probably use most of the time, can be easily changed to solve for mass instead of heat (Q). You just divide both sides of the equation by Cp and ΔT, resulting in the equation Q/CpΔT=m.
Q - 12 = 89 Add 12 to both sides of the equation. Q - 12 + 12 = 89 + 12 Q = 101
Do you mean 12Q = 89? Q = 89/12 Q = 7.4166666666666666666666
If you mean: 749 = 5q then the value of q is 749/5 = 149.8
If P varies directly with the square of Q then the equation would be in the form of P = kQ2, where k is the constant of variation so the new equation would be: P = 6Q2, so when Q = 12 we have P=6*122, or P = 864
yupe,its efficiency=Q/heating value of fuel
Depends on the equation. If it is similar to: Q = m*Cp*dT then Q = energy if it is similar to A= Ao * exp (-Q/RT) then Q is the activation energy
z = 2q/5 - 6
1, 5, 6, 6, 9, 10, 10, 11, 12, 13, 18 5 number summary: Minimum value = 1; Q 1 = 6; Median = 10; Q 3 = 12; Maximum value = 18; IQR = Q 3 – Q 1 = 12 – 6 IQR = 6. IQR x 1.5 = ? 6 x 1.5 = 9 9 + Q 3 = ? 9 + 12 = 21 (any value greater than 21 is an outlier)
Without prior knowledge of the value of q or r, it is impossible to calculate the answer to this equation.
It depends on whether the relationship between p and q is linear, quadratic, cubic etc or more complex. For example, if the relationship is quadratic, the equation q = 2p2 - 5p + 3 meets the requirements of the question and gives the value q = 9 when p = 3.386001 (approx).
4 x q=
amount of heat energy