Quite possibly 89.
To find q (the frequency of the green allele), use the Hardy-Weinberg equation: p^2 + 2pq + q^2 = 1. Given that 11% are green, q^2 = 0.11. Therefore, q = √0.11 ≈ 0.33.
If 59 out of 100 organisms are P, then the remaining organisms would be Q. Therefore, Q would be 41 out of 100 organisms.
To find the frequency of the "r" allele (q) in the population, divide the number of red organisms by the total number of organisms: 59/100 = 0.59. So, q = 0.59.
If the green allele is recessive and there are 28 organisms with green eyes, then the frequency of the green allele (q) would be √(28/Total organisms) = √(28/Total organisms). Since p+q=1, p = 1 - q. Substituting 28 for q gives 1 - √(28/Total organisms).
A. 0.45 Apex
To find q (the frequency of the green allele), use the Hardy-Weinberg equation: p^2 + 2pq + q^2 = 1. Given that 11% are green, q^2 = 0.11. Therefore, q = √0.11 ≈ 0.33.
If 59 out of 100 organisms are P, then the remaining organisms would be Q. Therefore, Q would be 41 out of 100 organisms.
If 30 out of 100 organisms are red, then the proportion of red organisms can be represented as ( q = \frac{30}{100} = 0.3 ) or 30%. Therefore, ( q ) is 0.3.
The question seems to be missing context regarding what "q" represents. If "q" refers to a proportion or percentage of red organisms, you could express it as a fraction of the total: for 59 red organisms out of 100, q would be 0.59 or 59%. If all 100 organisms are red, then q would be 1 or 100%. Please clarify if you need a different interpretation.
To find the frequency of the "r" allele (q) in the population, divide the number of red organisms by the total number of organisms: 59/100 = 0.59. So, q = 0.59.
If the green allele is recessive and there are 28 organisms with green eyes, then the frequency of the green allele (q) would be √(28/Total organisms) = √(28/Total organisms). Since p+q=1, p = 1 - q. Substituting 28 for q gives 1 - √(28/Total organisms).
, 0.34 Apex
0.16
There are 100 questions in this quiz.
A. 0.45 Apex
100 zeroes in a googal... the 'q' is a typo for a 'g'
P . . Q . . (P or Q)0 . . 0 . . . 00 . . 1 . . . 11 . . 0 . . . 11 . . 1 . . . 1=================P . . Q . . NOT(P and Q)0 . . 0 . . . . 10 . . 1 . . . . 11 . . 0 . . . . 11 . . 1 . . . . 0