-4.0 and -6.0
Let (x1, y1) = (4, 1) and (x2, y2) = (10, 9)The midpoint formula: [(x2 - x1)/2, (y2 - y1)/2]Substitute the given coordinates of the two points into formula:[(x2 - x1)/2, (y2 - y1)/2]= [(10 - 4)/2, (9 - 1)/2]=(6/2, 8/2)= (3, 4)Thus the midpoint is (3, 4).
Let the point A (x1, y1) = (2, 3) and B (x2, y2) = (4, 7). The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2] = [(2 + 4)/2, (3 + 7)/2] = [(6/2), (10/2)] = (3, 5) Thus, the midpoint is (3, 5).
Midpoint = (x1+x2)/2 and (y1+y2)/2 So the midpoint is (4, 5)
End points: (10, -4) and (2, 2) Midpoint: (6, -1) Distance from (6, -1) to (10, -4) = 5 Distance from (6, -1) to (2, 2) = 5 Equation of the circle: (x-6)^2 +(y+1)^2 = 25
midpoint between 4-16
Points:(4, 3) and (10, -5) Midpoint: (4+10)/2, (3-5)/2 = (7, -1)
If you mean points of (-2, 3) and (10, 3) then the midpoint is (4, 3)
Let (x1, y1) = (4, 1) and (x2, y2) = (10, 9)The midpoint formula: [(x2 - x1)/2, (y2 - y1)/2]Substitute the given coordinates of the two points into formula:[(x2 - x1)/2, (y2 - y1)/2]= [(10 - 4)/2, (9 - 1)/2]=(6/2, 8/2)= (3, 4)Thus the midpoint is (3, 4).
If you mean points of (-4, 6) and (4, -2) then the midpoint is at (0, 2)
If you mean points of (-4, 6) and (4, -2) then the midpoint is at (0, 2)
Points: (-4, 6) and (4, -2) Midpoint: (0, 2)
Endpoints: (2, 4) and (2, -4) Midpoint: (2, 0)
midpoint between 4-16
The midpoint is going to have an x and y value halfway between those of the two endpoints. The midpoint has an x value 6 higher than the first endpoint and a y value 4 lower. Just continue this pattern to get the other endpoint. (-2+6, 6-4)=(4, 2) The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2] By substituting the given values into the formula we have: (x1 + -8)/2 = -2 and (y1 + 10)/2 = 6 x1 - 8 = -4 and y1 + 10 = 12 x1 -8 + 8 = -4 + 8 and y1 + 10 - 10 = 12 - 10 x1 = 4 and y1 = 2 Thus, the other endpoint is (4, 2).
Points: (-1, -9) and (4, -2) Midpoint: (3/2, -11/2)
Endpoints: (-2,-2) and (4, 6) Midpoint: (1, 2)
The midpoint is at (3, 4)