two
15 letters
bookkeeper
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Five thousand
The number of permutations of the letters PENCIL is 6 factorial, or 720.
Make notes that:There are 2 c's in the given word.There are 2 o's in the given word.Since repetition is restricted when rearranging the letters, we need to divide the total number of ways of rearranging the letters by 2!2!. Since there are 9 letters in the word to rearrange, we have 9!. Therefore, there are 9!/(2!2!) ways to rearrange the letters of the word 'chocolate'.
The number of permutations of the letters of the word depends upon the number of letters in the word and the number of repeated letters. Since there are nine letters, if there were no repetitions, the number of ways to rearrange these letters would be 9! or 9 X 8 X 7 X 6 X 5 X 4 X 3 X 2 X 1. But don't do the multiplication just yet. To account for the repeated letters, we need to divide by 3! (for the 3 Ns) by 2! (for the 2Es) and by another 2! (for the 2 Ss). This gives a final answer of 15,120 permutations of these letters.
5
CHEESE cheese has 6 letters in it. if you have a word with different letters, you do the factorial of the number of letters there are. but you can not do that in this word. since it has 3 E's, then you mut do 6!(factorial) divided by 3! then the answer would be 120
To solve Fortress Riddle number 6, you must rearrange the letters in the word "scaffold" to form another word. The word you are looking for is "floods."
In the word "function" you have 8 letters. 6 different letters and 2 equal letters.The number of different arrangements that are possible to get are:6!∙8C2 = 720∙(28) = 20 160 different arrangements.
The minimum number of ports on most brands of switches is four. While there is no industry rule that limits the number of ports on a single switch, practical application has shown that a minimum of four ports is about right.
The word "educational" is an example of a word where no matter how you rearrange the letters, the new arrangement will always form a genuine word, such as "educational," "education," "auctioned," and so on.
9! (nine factorial)However, since the S is repeated 4 times you need to divide that by 16, and since the E is repeated once, you need to divide that by 2. The final result, which is the number of distinctcombinations of the letters POSSESSES is 11340.
Switches increase the number of collision domains in the network.
Firstly, Portuguese has 26 letters. Secondly, every language, including Portuguese is written with at least the minimum number of symbols required to represent that language.