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What is the molality of solution that has 3 mol of glucose in 6 Kg of water?
Wiki User
∙ 11y ago
3mol/6kg
Wiki User
∙ 11y ago
The molality of a solution is the number of moles of solute per kilogram of solvent. In this case, you have 3 mol of glucose dissolved in 6 kg of water. First, convert 6 kg of water to 6000 g. Then, calculate the molality using the formula: molality = moles of solute / kg of solvent. This gives you a molality of 0.5 mol/kg.
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What is the molality solution that has 3 mol of glucose in 6 kg if water?
The molality of the solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 3 mol of glucose in 6 kg of water. Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution that has 3 mol of glucose in 6 kg of water?
The molality of the solution is 0.5 mol/kg. This is calculated by dividing the number of moles of solute (3 mol glucose) by the mass of solvent in kilograms (6 kg water).
What is the molality of a solution that has 6 mol of cacl2 in 3kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
What is the molality of a solution the has 3 mol of glucose on 6 kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality would be 0.5 mol/kg since there are 3 moles of glucose in 6 kg of water.
What is the molality of a solution that has 6 mol of CaCl2 in 3km of water?
The molality of the solution is 2 mol/kg. Molality is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, there are 6 moles of CaCl2 and 3 kg of water.
What is the molality solution that has 3 mol of glucose in 6 kg if water?
The molality of the solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 3 mol of glucose in 6 kg of water. Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution that has 3 mol of glucose in 6 kg of water?
The molality of the solution is 0.5 mol/kg. This is calculated by dividing the number of moles of solute (3 mol glucose) by the mass of solvent in kilograms (6 kg water).
What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?
4 mol over 0.800 kg
What is the molality of a solution that has 6 mol of cacl2 in 3kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
What is the molality of a solution that has 6 mol of CaCl2 in 3km of water?
The molality of the solution is 2 mol/kg. Molality is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, there are 6 moles of CaCl2 and 3 kg of water.
What is molality of a solution that has 4 mol of KCI in 0.800 kg of water?
4 mol/0.800 kg
What is the molality of a solution containing 10.0g of Na2SO4 dissolved in 1000.0g of water?
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
What is the molality of a solution the has 3 mol of glucose on 6 kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality would be 0.5 mol/kg since there are 3 moles of glucose in 6 kg of water.
What is the molality of a solution that has 6 mol of CaCl2 in 3 kg of water?
2 m
What is the molality of a solution that contains 5.10 mol KNO3 in 4.47 kg water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality would be 5.10 mol KNO3 / 4.47 kg H2O = 1.14 mol/kg.
What is the molality of a solution made by dissolving 2 mole of NaOH in 6kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality would be 2 mol / 6 kg = 0.33 mol/kg.
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
0.2
