A molecular mass is found by adding all of the masses of the atoms for that molecule. In NaH2PO4, we have:
Na: 1 atom x 23amu/atom = 23
H: 2 atoms x 1.0 amu/atom = 2
P: 1 atom x 31amu/atom = 31
O: 4 atoms x 16amu/atom = 64
Add those together, and NaH2PO4 has a molecular mass of... 120.
Actually H3PO4 is a molecular formula referring to the compound we know as Phosphoric acid. It doesn't indicate number of moles of H3PO4. But the number of moles can be found out if the amount in mass or some other measurable quantity(e.g. conc. in solution) is given. The molar mass(mass of 1 mole) of H3PO4 is 98 grams. So if mass is given then it can be converted to grams and dividing by molar mass(i.e 98) we get number of moles. moles of H3PO4 =(mass of H3PO4 in grams)/98. 1 mole of H3PO4 has ->3 moles of H atoms. ->1 mole of P atoms. ->4 moles of O atoms. ( 1 mole=6.0225 *1023 units)
The percent composition of phosphoric acid (H3PO4) can be calculated as follows: Percentage of hydrogen (H): (3 x atomic mass of H) / molar mass of H3PO4 Percentage of phosphorus (P): (atomic mass of P) / molar mass of H3PO4 Percentage of oxygen (O): (4 x atomic mass of O) / molar mass of H3PO4 These values can be used to determine the percent composition of each element in phosphoric acid.
As given 'Na3PO4' it is impossible to tell, because you also need the mass of sodium phosphate. Then use the eq'n moles = mass(g) / Mr From the Periodic Table we can calculate the Mr. Naa x 3 = 23 x 3 = 69 P x 1 = 31 x 1 = 31 O x 4 = 16 x 4 = 64 69 + 31 + 64 = 164 164 is the Relative molecular mass (Mr) of sodium phosphate. However, mass(g) = 1 mole X 164(Mr) mass of 1 mole = 164 grams. Similarly mass(g) = 2 moles X 164(Mr) mass of 2 moles = 328 grams. et seq., So you need to know the mass in order to calculate the moles.
One mole of phosphoric acid (H3PO4) contains three moles of hydrogen atoms. This is because there are three hydrogen atoms in each molecule of phosphoric acid. Each mole of phosphoric acid contributes three moles of hydrogen atoms to the overall chemical formula.
One mole of 12C has a mass of 12.00000 grams (exactly, by definition).One mole of 13C has a mass of 13.00335 grams.One mole of 14C has a mass of 14.00324 grams.One mole of natural carbon - i.e. a sample with the ratio of isotopes equal to that in nature - has a mass of 12.0107 grams.
Actually H3PO4 is a molecular formula referring to the compound we know as Phosphoric acid. It doesn't indicate number of moles of H3PO4. But the number of moles can be found out if the amount in mass or some other measurable quantity(e.g. conc. in solution) is given. The molar mass(mass of 1 mole) of H3PO4 is 98 grams. So if mass is given then it can be converted to grams and dividing by molar mass(i.e 98) we get number of moles. moles of H3PO4 =(mass of H3PO4 in grams)/98. 1 mole of H3PO4 has ->3 moles of H atoms. ->1 mole of P atoms. ->4 moles of O atoms. ( 1 mole=6.0225 *1023 units)
1 mole of P4O10 reacts with 6 moles of water to produce 4 moles of H3PO4. Therefore, 10.0 moles of water will produce (10/6)*4 moles of H3PO4. To convert moles to grams, multiply the number of moles by the molar mass of H3PO4.
To solve this problem, you will need to use the balanced chemical equation provided to determine the mole ratios between the reactants and products. First, convert the volume of H3PO4 to liters by dividing by 1000 mL/L: 750 mL H3PO4 / 1000 mL/L = 0.750 L H3PO4 Next, convert the concentration of H3PO4 to moles/L: 6.00 M H3PO4 = 6.00 mol/L H3PO4 Now, use the volume and concentration to calculate the number of moles of H3PO4: 0.750 L H3PO4 * 6.00 mol/L H3PO4 = 4.50 mol H3PO4 Since the chemical equation shows a 1:1 mole ratio between H3PO4 and Ca(OH)2, there must be 4.50 mol Ca(OH)2 as well. To determine the mass of each product, you will need to know the molar masses of each compound. The molar mass of H3PO4 is 98.00 g/mol, and the molar mass of Ca(PO4)2 is 212.09 g/mol. Therefore, the mass of H3PO4 produced in the reaction is: 4.50 mol H3PO4 * 98.00 g/mol = 434.00 g H3PO4 And the mass of Ca(PO4)2 produced in the reaction is: 4.50 mol Ca(PO4)2 * 212.09 g/mol = 953.41 g Ca(PO4)2 These are the masses of each product that would be produced if 750 mL of 6.00 M H3PO4 reacts according to the given chemical equation.
The percent composition of phosphoric acid (H3PO4) can be calculated as follows: Percentage of hydrogen (H): (3 x atomic mass of H) / molar mass of H3PO4 Percentage of phosphorus (P): (atomic mass of P) / molar mass of H3PO4 Percentage of oxygen (O): (4 x atomic mass of O) / molar mass of H3PO4 These values can be used to determine the percent composition of each element in phosphoric acid.
As given 'Na3PO4' it is impossible to tell, because you also need the mass of sodium phosphate. Then use the eq'n moles = mass(g) / Mr From the Periodic Table we can calculate the Mr. Naa x 3 = 23 x 3 = 69 P x 1 = 31 x 1 = 31 O x 4 = 16 x 4 = 64 69 + 31 + 64 = 164 164 is the Relative molecular mass (Mr) of sodium phosphate. However, mass(g) = 1 mole X 164(Mr) mass of 1 mole = 164 grams. Similarly mass(g) = 2 moles X 164(Mr) mass of 2 moles = 328 grams. et seq., So you need to know the mass in order to calculate the moles.
To determine the volume of H3PO4 required to react with 4.5 grams of Zinc, we need to convert the mass of Zinc to moles using its molar mass (65.38 g/mol). Then, we use the stoichiometry of the balanced chemical equation to find the corresponding mole ratio between H3PO4 and Zinc (Zn). Finally, we convert the moles of H3PO4 to liters using its molarity (3.0 M).
H3PO4 is the formula of phosphoric acid. 3 x 1.01 +1 x 30.97 + 4 x 16 = 98.0 g / mole
One mole of phosphoric acid (H3PO4) contains three moles of hydrogen atoms. This is because there are three hydrogen atoms in each molecule of phosphoric acid. Each mole of phosphoric acid contributes three moles of hydrogen atoms to the overall chemical formula.
First, calculate the moles of water: 175g / 18.0116 g/mol = 9.721 moles. The total moles in the solution is the sum of water and phosphoric acid (H3PO4) moles. Next, calculate the mole fraction of H3PO4: moles of H3PO4 / total moles in the solution. This will give you the mole fraction of phosphoric acid in the solution.
One molecule of P2O3 = 1 mole. Go to the periodic table P = 30gm x 2 = 60 gm. O= 16 gm x 3 = 48 mg. Total is 60 + 48 = 108 gm is the weight of one molecule which is also the number of grams in 1 mole (remember 1 mol = 1 mole). So since you have 37.9 grams divide this by 108 and you have .35 moles.
each mol of h3po4 has 6.022*10^23 molecules you have 1.5 mol, so 1.5 * 6.022*10^23 molecules = 9.033*10^23 molecules each molecule of h3po4 has 1 atom of p, so you have 9.033*10^23 atoms p.
The molar mass of ferric ammonium citrate is approximately 270.00 g/mol.