The value is 0,944.
It would be 0.94 M (to 2 sig figs)
Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========
Molarity= No. of moles of solute/Volume of solution(in litre) or No. of moles of solute*1000/Volume of solution(in ml)
The molarity of a solution containing 7.0 moles of solute in 569mL of solution is a)81M b)0.081M c)12M D)4.0M The answer is C. 12M 7 x 1000/569 = 12.302
The concentration in moles of a substance in the solution
The number of moles of a solute per kilogram of solvent. (Apex)
Molarity = moles solute/ Liters solution
moles of solute/L of solution
You need to know the moles of solute and the VOLUME of SOLUTION.
Molarity = moles of solute/Liters of solution Without the solute name the mass ( 8 grams ) does no good. Mass of solute (1 mole/molar mass of solute) = moles solute ----------------------then use Molarity equation. ( remember convert to liters )
Increasing the amount of the solute in the solution the molarity and the density of this solution increases.
The number of moles of solute dissolved in 1 L of a solution would be the molarity. As an example, if you had 2 moles of solute in 1 liter the molarity would be 2M.
Molarity = moles of solute/Liters of solution