Want this question answered?
The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
No this is not an ideal solution, because water and alcohol (ethanol) molecules interact rather complex resulting in eg. an azeotropic boiling point at 96% mixture
3 quarts = 96 oz
54 A+
96/2.54 inches 37.8 in Algebraic Steps / Dimensional Analysis Formula 96 cm*1 in 2.54 cm=37.79527559 in
96%
The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
The GCF is 24.
500+96+800+11
dick
50-500 USD or so
50-500 usd
.006" for the 96-00
96
100-500 USD or so
To find the molarity, we can set up the following factor labeling problem. Note that a specific gravity of 1.84 can be treated as a density of 1.84 g/ml. The molar mass of sulfuric acid (H2SO4) is 98.079 g /molM(mol/l)= (1.84 g/ 1 ml)(1000 ml/1 l)(1 mol/98.079 g)(.96 purity)= 18 mol/l= 18 MThe molarity is 18 mol/l. The pH of this solution would be -1.26...VERY ACIDIC.
First calculate how much ethanol you need in the final solution. 55% X 2.5l = 1.375l Then calculate how much ethanol you already have in the solution. 0.5l X 70% = 0.35l Now take the difference between those two numbers as the extra amount needed. 1.375l - 0.35l = 1.025l Now correct for the fact that you are adding only 96% ethanol. 1.025l / 96% = 1.068l Answer: 1.068l