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0.829 M is the molarity.

The formula is:

mL x M = millimoles of substance

millimoles of NaOH = millimoles of HCl

mL x M = mL x M

28.6 x 0.145 = 5.00 x M

M = 0.829

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9y ago
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10y ago

1 Na2CO3 / 2 HCl

28.45 mL HCl

1 L

1000 mL

= .02845 L

.1586 g Na2CO3

1 mol

105.98 g

= .0014965088 mol

.0014965088 mol

.02845 L

= .0526013629

.0526013629 x 2 = .1052027259 = .1052 M

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10y ago

28.6ml/10ml*.175M = .5005 M then with significant figured the answer is 0.501 M

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9y ago

The molarity is 0.496m.

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Q: What is the molarity of an hcl solution if 10.0ml hcl solution is titrated with 28.6ml of 0.175m naoh solution?
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