There are three of these compounds. Oxygen difluoride is v-shaped. Since it's difficult to offer diagrams on answers.com let me suggest that you consult wikipedia for information about the other compounds.
Oxygen fluoride is a bent molecule.
Oxygen fluoride is a molecular compound which is formed by covalent bonds.
Methanol has a tetrahedral shape. Oxygen by itself would have a bent shape when bonded with hydrogen and carbon
Substances which can oxidize molecular Oxygen(O2) are =Fluorine(F2) - It will oxidize Oxygen to +2 oxidation state:F2 + O2 ----> OF2 (Oxygen difluoride)Platinum(VI) Fluoride - It will oxidize Oxygen to +1/2 Oxidation state:O2 + PtF6 ----> O2PtF6 (Dioxygenyl Hexafluoroplatinate)
Oxygen dibromide has a bent molecular shape due to the presence of two lone pairs on the oxygen atom, which repel the bonded bromine atoms. The molecule is also polar due to the difference in electronegativity between oxygen and bromine atoms.
XeF4 reacts with water - or even moisture in the air - to release pure xenon, hydrogen fluoride and molecular oxygen.
The sulfate ion (SO42-) has a tetrahedral molecular shape. This shape is formed by the central sulfur atom bonded to four oxygen atoms, with the oxygen atoms arranged in a symmetrical tetrahedral configuration around the sulfur atom.
So the overall shape of the molecule can be described as two trigonal planar nitro groups connected by a shared bent oxygen between them..or can say V-shape
Yes, sodium fluoride is a molecular compound. It consists of individual sodium ions (Na+) and fluoride ions (F-) that are ionically bonded together in a fixed ratio.
Since Na2O is an Ionic compound. it does not have any shape.
Calcium Fluoride is CaF2. Therefore, its molecular mass = mass(Calcium + 2 x Flourine) = 40 + 2x19 = 78 u.
The molecular formula for iron(III) fluoride is FeF3. In solution, it dissociates into Fe3+ ions and F- ions.