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mass moment of inertia is the property of the body to resist rotation about the given axis where as the area moment of inertia is the resistance to bending about the given axis
Moment of inertia is a property of a rotating body that defines its resistanceto a change in angular velocity about an axis of rotation.===========================By carefully reading and analyzing the treatment above, we arelead to infer that the actual answer to the question is 'yes'.
moment of inertia is the rotational equivalent of mass. it is given by I= Mk2 moment of inertia in rotational motion play the same role as mass in linear motion, that is in linear motion f = ma while in rotation, torque= I*Angular acceleration where I is the moment of inertia
Angular momentum about the axis of rotation is the moment of linear momentum about the axis. Linear momentum is mv ie product of mass and linear velocity. To get the moment of momentum we multiply mv by r, r the radius vector ie the distance right from the point to the momentum vector. So angular momentum = mv x r But we know v = rw, so angular momentum L = mr2 x w (w-angular velocity) mr2 is nothing but the moment of inertia of the moving body about the axis of rotation. Hence L = I w.
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mass moment of inertia is the property of the body to resist rotation about the given axis where as the area moment of inertia is the resistance to bending about the given axis
The axis about which the body is being rotated and the geometry of the body are important. The further away material (in terms of area) is from the centroid of the body the higher the moment of inertia will be, which is why an I-beam is good in bending. If it's the mass moment of inertia which is used in dynamics for Euler's angular momentum equation. Then the mass of the body is important. The further away mass is from the axis of rotation the greater the mass moment of inertia will be. This is why when a figure skater pulls their arms into her body during a spin she begins to spin faster. The mass of their arms is now closer to their axis of rotation lowering their mass moment of inertia and decreasing their resistance to rotation.
A rotating body that spins about an external or internal axis (either fixed or unfixed) increase the moment of inertia.
Moment of inertia is a property of a rotating body that defines its resistanceto a change in angular velocity about an axis of rotation.===========================By carefully reading and analyzing the treatment above, we arelead to infer that the actual answer to the question is 'yes'.
This is known as parallel axes theorem. Statement: If IG be the moment of inertia of a body of mass M about an axis passing through its centre of gravity, then MI (I) of the same body about a parallel axis at a distance 'a' from the previous axis will be given as I = IG + M a2
The moment of inertia (writen I, with an indice indicating the axis in which it is expressed) mesures the opposition any kind of body will have against a certain momentum (along that same axis) trying to rotate that body
The moment of inertia of a cube depends on what its axis of rotation is. About an axis perpendicular to one of its sides and through the centre of the cube is (ML2)/6. Where M is the Mass of the Cube and L the length of its side. Due to the symmetry of the cube, you can find the Moment of Inertia about almost any other axis by using Parallel and Perpendicular Axis Theorems.
the moment of inertia of a body about a given axis is equal to the sum of its moment of inertia about a parallel axis passing through its centre of mass and the product of its mass and square of perpendicular distance between two axis Iz=Ix+Iy
moment of inertia is the rotational equivalent of mass. it is given by I= Mk2 moment of inertia in rotational motion play the same role as mass in linear motion, that is in linear motion f = ma while in rotation, torque= I*Angular acceleration where I is the moment of inertia
Angular momentum about the axis of rotation is the moment of linear momentum about the axis. Linear momentum is mv ie product of mass and linear velocity. To get the moment of momentum we multiply mv by r, r the radius vector ie the distance right from the point to the momentum vector. So angular momentum = mv x r But we know v = rw, so angular momentum L = mr2 x w (w-angular velocity) mr2 is nothing but the moment of inertia of the moving body about the axis of rotation. Hence L = I w.
If Torque(τ) = 0, L=Iω=constant. Therefore, ω will remain conserved if the moment of inertia (M.I.) of the body about a given axis of rotation remains constant.
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