well BrF3 will auto dissociate to give BrF4- + BrF2+ ...the KF will give a F- to the BrF3 obviously this giving is really due the higher electronegativity of the fluorine thus their will be an increase in the amounts of BrF4- in solution .Using the solvent-system definition of an acid or base.Any specie (molecule ,ion)which increases the anionic or negatively charged amounts of species in solution is a base.So KF definitely behaves as a base. You can use this same reasoning for SnF4 and try and figure that one out on your own.good luck .
sp3d2, this accounts for all 6 electron domains found around the central Br atom. Verify by checking the Lewis dot configuration. Br has 4 bonded electron domains and 2 lone pairs. Therefore the hybridization of the central atom in BrF4 is sp3d2
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a. Name: BerylliumSymbol: Beb. Name: MagnesiumSymbol: Mgc. Name: CalciumSymbol: Cad. Name: StrontiumSymbol: Sre. Name: BariumSymbol: Baf. Name: RadiumSymbol: Ra
Square planar
Tetrahedral
Begin this dot structure with a B atom in the center. In each cardinal direction is one singly bonded F atom with three pairs of dots. The structure is then bracketed and a superscript of 1- is added.
Most think is 90 and 180 degrees. the correct answer is 90.84, 89.20 and 179.9 degrees. This is due to the difference in distances between Br and the four Fs, which are not equal; they are 2.017 and 2.15.
well BrF3 will auto dissociate to give BrF4- + BrF2+ ...the KF will give a F- to the BrF3 obviously this giving is really due the higher electronegativity of the fluorine thus their will be an increase in the amounts of BrF4- in solution .Using the solvent-system definition of an acid or base.Any specie (molecule ,ion)which increases the anionic or negatively charged amounts of species in solution is a base.So KF definitely behaves as a base. You can use this same reasoning for SnF4 and try and figure that one out on your own.good luck .
Seesaw, as Br = 5 valence electrons, 1 electron for each F, one electron for the negative charge means it's a trigional byprimidal, however there is one unpaired set of electrons meaning it's a seesaw shape
sp3d2, this accounts for all 6 electron domains found around the central Br atom. Verify by checking the Lewis dot configuration. Br has 4 bonded electron domains and 2 lone pairs. Therefore the hybridization of the central atom in BrF4 is sp3d2
When you do the VSEPR you get 6pairs of electron pairs and two lone pairs which means that when you look at the geometrical shape (by looking at how many pairs of electrons you got and in this cases its 6) the shape is octahedral but the molecular shape is square planar because you only have four atoms bonding and two lone pairs which means that the lone pairs have to be as far from each other as possible so they go on the two ends ( one on top and one on the bottom) which leavs the shape to be a square planar! i hope this helps you good luck. --------- TL;DR: Square Planar.
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[Name] Rave [Name] Riot [Name] Reverse [Name] Reckless [Name] Reject [Name] Restless [Name] Radical? [Name] Radiant [Name] Ran [Name] Rabi [Name] React [Name] RAWR [Name] Ready [Name] Radiation?