Sicily is the largest
Find the largest of two, then find the largest of that value and the third value. int* max (int* a, int* b) { return (a*) > (b*) ? a : b; } int* max_of_three (int* a, int* b, int* c) { return max (max (a, b), c); }
#include <iostream.h> #include <conio.h> void main() { clrscr(); int largest(int,int,int); cout<<"Enter 3 Integer Numbers\n"; int a,b,c; cin>>a>>b>>c; int result; result=largest(a,b,c); cout<<"\n\nLargest Value of Inputed is "<<result; getch(); } inline largest(int a,int b,int c) { int z; z=(a>b)?((a>c)?a:c):((b>c)?b:c); return(z); }
To find the largest of three numbers, first find the largest of two numbers: int max (int x, int y) { return x<y?y:x; } Now you can use this one function to find the largest of three numbers: int max (int x, int y, int z) { return max (max (x, y), z); }
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// return the larger of any 2 numbers int larger (int a, int b) { return a>b?a:b; } // return the largest of any 3 numbers int largest (int a, int b, int c) { return larger (larger (a, b), c)); } // return the middle value of any 3 numbers int middle (int a, int b, int c) { if (a>b) a^=b^=a^=b; // swap a and b (b is now the larger of the two) if (b>c) b^=c^=b^=c; // swap b and c (c is now the largest of all three) return larger (a, b); // return the larger of a and b }
To find the largest of three numbers you must first find the largest of two numbers: int max (int a, int b) { return a>b?a:b; // or, equivalently: if (a>b) return a; else return b; } Now we can use this function to find the maximum of three: int max3 (int a, int b, int c) { return max (max (a,b), c); }
int lastLargestIndex(int a[],int n) //a=array, n= number of elements in array { int max=a[0],maxp=0; //max=largest no., maxp= position of largest no. for(int i=0;i<n;i++) if(a[i]>=max) { max=a[i]; maxp=i; } return maxp; }
Implement these methods: public static int smallest(int[] arr) { int small = arr[0]; for(int i = 1; i < arr.size(); i++) if(arr[i] < small) small = arr[i]; return small; } public static int largest(int[] arr) { int large = arr[0]; for(int i = 1; i < arr.size(); i++) if(arr[i] > large) large = arr[i]; return large; }
int max (int a, int b) { return a<b?b:a; } int max3 (int a, int b, int c) { return max (max (a, b), c); }
#include<stdio.h> // returns the index of the largest value in the array int max (int a[], unsigned size) { if (!size) return -1; // invalid array int index = 0; // assume index 0 holds the largest value (so far) for (int i=1; i<size; ++i) { // traverse the remainder of the array if (a[i]>a[index]) { // compare with the current largest index = i; // the current value is larger } } return index; // a[index] holds the largest value } int main (void) { int x[10] = {7, 4, 3, 9, 5, 2, 1, 8, 6}; printf ("The largest value in the array is %d\n", max (x, 10)); return 0; }
int max(int arr[], int arrSize){int maximum = arr[0];for (int i = 0; i < arrSize; i++){if (maximum < arr[i]){maximum = arr;}}return maximum;}
It is 'long long int' meaning 64 bit (8 byte).