There is not enough information to answer this question.
If the object is moving along a horizontal surface with a constant acceleration,then the net vertical force on it is zero, and the net horizontal force on it is(the pushing force) minus (any kinetic friction force where it rubs the surface).The numerical value of that net force is(the acceleration) times (the object's mass).
This would be known as the net-force.
If it doesn't move, it doesn't accelerate; therefore the net force must be zero.
Work = (force) x (distance) = 30 x 9 = 270 joules
Inertia will not be affected when "net" or "net force" is zero.
It is acceleration in the horizontal direction. This would happen as a result of a net horizontal force acting on a body.
If the object is moving along a horizontal surface with a constant acceleration,then the net vertical force on it is zero, and the net horizontal force on it is(the pushing force) minus (any kinetic friction force where it rubs the surface).The numerical value of that net force is(the acceleration) times (the object's mass).
If the horizontal velocity is constant, then the horizontal acceleration is zero,and the net horizontal force is zero.But if you are saying that the body was in constant motion and after that the force was applied, then the body will acccelerate because of the force. The net force applied on the body would be equal to the force applied to it when the body was in constant motion as here the force is in direction of the motion and hence the angle will be 0 giving the value of cos 0º as 1. Hence there would be no reduction in the net force
Net force is 150N - 25N, or 125N. By Newton's Second Law of motion, acceleration is force divided by mass, so acceleration is 125N divided by 45kg, or 2.78 m s-2.Note: This is a "trite" example, because friction is dependent on velocity, but the question provided a fixed friction. Also, mass varies with time as fuel is consumed, but again the question did not provide those details.
Yes, but any bit of force in any horizontal direction is always exactly cancelled by an equal-size bit of force in the opposite horizontal direction, so there's never a NET horizontal buoyant force. It's only apparent in the upward vertical direction.
perpendicular to the ball's path
net force
It wouldn't accelerate. It would move at a constant velocity due to its tendency to keep moving (inertia) and friction being canceled out by the horizontal force.
you need 350N to be added to 250 so that it can equal the same amount and creating no net force.
This would be known as the net-force.
ace is a hard horizontal strokes that is straight and close to the net
F=maF= 15 x 10F= 150N