40+50 = 90, unless i'm misunderstanding the question
When adding forces acting in different directions, you need to consider both the direction and magnitude of each force. If the forces are acting in opposite directions, you need to subtract the force in one direction from the force in the other direction to find the resultant force. In this context, the Newton is a unit of force, not a mathematical operation.
It will be the vector sum of the forces. Since in this case they are acting in the same direction we can ignore the vector bit so 30 + 10 = 40 Newton
in the same direction as the net force, directly proportional to it, and inversely proportional to the object's mass.
Having no force acting at all, as the forces will cancel each other out. This results in a net force of zero.
10N if both forces are in the same direction.
It is the same as adding a positive and adding a negative number
Forces are vector quantities. This means they have both a magnitude and direction associated with them. If you add vectors going in the opposite directions it is the same as subtracting one from the other. Therefore, the resultant force is the difference between the forces.
This is the simplest case of vector addition. If two forces are acting in the same direction, then you can just add them, to get the net force.
This is the simplest case of vector addition. If two forces are acting in the same direction, then you can just add them, to get the net force.
To calculate the net force when two or more forces are acting in the same direction, simply add the magnitudes of the individual forces together. The net force will be the sum of the forces acting in the same direction.
To find the net force of two objects acting in the same direction, simply add the individual forces together. The net force will be the sum of the individual forces acting on the objects.
According to Newton's 3rd law, every force has an equal and opposite reaction force. Therefore, the reaction force on an object, is the exact same force it applied on another object, with the reverse direction.