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What is the net force of a boy that stands on a floor with a mass of 45kg?
Wiki User
∙ 12y ago
Since the bed is uniform we can assume that each leg carries exactly 1/4 the total force. Force is equal to mass times the acceleration of the object. The bed, hopefully being at rest, is only effected by gravity. So its acceleration is 9.8 m/s2 downward.
F = 45Kg * 9.8 m/s2
This will give you an answer in Newtons (Kg*m/s2) then divide by 4.
Wiki User
∙ 13y ago
Wiki User
∙ 12y agoWe have to remember two things here:
- Net force is the vector sum of all forces acting on the body in question(the boy, in this case).
- According to Newton's first law, an object at rest remains at rest and an object in motion stays n motion with the same speed in the same direction unless there is a net force acting on the object.
Here, the boy is standing, and he remains motionless, which means there is no net force acting on him.
This is because there are two forces acting, which cancel each other out(and thus, no net force). The first is the boy's weight, which is exerted on the floor by the boy(downwards). The second force is the normal reaction force, which is exerted on the boy by the floor(upwards). These two forces are balanced, which means the net force is zero.
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