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How does the weight of a falling body compare with the air resistance it encounters before it reaches terminal velocity?
The weight exceeds the force of air resistance, but as the speed increases the air resistance increases, so the net force (weight - air resistance) falls. When the difference becomes zero the acceleration ceases and you have terminal velocity.
What is the net force when 10 N encounters 15 N of air resistance?
Since from the description it seems that the forces act in opposite directions, you simply subtract.
What is the net force acting on a freely falling 1-kg ball if it encounters 2 N of air resistance?
The idea is to calculate the downward force of gravity, and then subtract the air resistance, since it acts in the opposite way. This assumes that the ball falls directly downward.
What is the net force acting on a falling 1-kg rm kg ball if it encounters 2 N rm N of air resistance?
Since gravity attracts the ball downward, and air resistance acts upwards (assuming that it falls straight down), you need to subtract the force of gravity (i.e., the weight) minus the air resistance.
When a 10 newton falling body encounters 4 newtons of air resistant the net force on the body is?
6 newtons, so it keeps accelerating. As it does, the air resistance increases until it reaches 10 newtons so then the net force is zero and then the fall continues at constant speed (the terminal velocity).
What is the net force that acts on a 10N falling object when it encounters 4N of air resistance?
The net force is the difference between the 10N falling object and the 4N of air resistance So you solve 10N-4N is 6N
When a 25 n falling object encounters 15 n of air resistance the net force on it is.?
25-15= 10n
How does the weight of a falling body compare with the air resistance it encounters before it reaches terminal velocity?
The weight exceeds the force of air resistance, but as the speed increases the air resistance increases, so the net force (weight - air resistance) falls. When the difference becomes zero the acceleration ceases and you have terminal velocity.
What is the net force acting on a 12-N falling object when it encounters 12-N of air resistance?
The net force would be zero, which means the falling object would no longer be accelerating, and would be falling at terminal velocity, which is a constant velocity. Weight is a downward (negative) force and air resistance is an upward (positive) force. Fnet = weight + air resistance = -12N + 12N = 0N
What is the net force when 10 N encounters 15 N of air resistance?
Since from the description it seems that the forces act in opposite directions, you simply subtract.
What is the net force acting on a freely falling 1-kg ball if it encounters 2 N of air resistance?
The idea is to calculate the downward force of gravity, and then subtract the air resistance, since it acts in the opposite way. This assumes that the ball falls directly downward.
What do you get when the force of air Resistance from the force of gravity?
The net force on a following object
What is the net force acting on a falling 1-kg rm kg ball if it encounters 2 N rm N of air resistance?
Since gravity attracts the ball downward, and air resistance acts upwards (assuming that it falls straight down), you need to subtract the force of gravity (i.e., the weight) minus the air resistance.
How does the force of gravity on a raindrop compare with the air drag it encounters when it falls at a constant velocity?
If the vertical speed is constant, that means there is zero vertical acceleration. If the vertical acceleration is zero, that means the net vertical force on the object is zero. If the net vertical force on the object is zero, that means the downward force (weight) and upward force (air resistance) are equal.
When a 10 newton falling body encounters 4 newtons of air resistant the net force on the body is?
6 newtons, so it keeps accelerating. As it does, the air resistance increases until it reaches 10 newtons so then the net force is zero and then the fall continues at constant speed (the terminal velocity).
A 20 N falling object encounters 4 N of air pressure what is the magnitude of the net force on the object?
The object experiences 20 newtons pulling it down due to gravity. But it also experiences 4 newtons air resistance pushing it up. 20 - 4= 16 newtons net downward force on the object.
What is the net force that acts on a 10-N freely falling object?
the net force is 10N - it is acceleratiing with gravity - if no air resistance. If it falls far enough, eventually air resistance will balance the force and net force will be zero - it will fall at constant velocity and zero acceleration
