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When a N parachutist opens his chute and experiences 800 N of air resistance the net force on him is?
Net force = Force of gravity - Force of air resistance = weight - air resistance = mg - 800N.
What is the net force acting on a falling 1-kg rm kg ball if it encounters 2 N rm N of air resistance?
Since gravity attracts the ball downward, and air resistance acts upwards (assuming that it falls straight down), you need to subtract the force of gravity (i.e., the weight) minus the air resistance.
What is the net force acting on a freely falling 1-kg ball if it encounters 2 N of air resistance?
The idea is to calculate the downward force of gravity, and then subtract the air resistance, since it acts in the opposite way. This assumes that the ball falls directly downward.
How does the weight of a falling body compare with the air resistance it encounters before it reaches terminal velocity?
The weight exceeds the force of air resistance, but as the speed increases the air resistance increases, so the net force (weight - air resistance) falls. When the difference becomes zero the acceleration ceases and you have terminal velocity.
A 20 N falling object encounters 4 N of air pressure what is the magnitude of the net force on the object?
The net force on the falling object is the difference between the gravitational force pulling it down (20 N) and the air resistance force pushing against it (4 N). Therefore, the magnitude of the net force on the object is 16 N.
What is the net force that acts on a 10N falling object when it encounters 4N of air resistance?
The net force is the difference between the 10N falling object and the 4N of air resistance So you solve 10N-4N is 6N
When a 25 n falling object encounters 15 n of air resistance the net force on it is.?
25-15= 10n
When a N parachutist opens his chute and experiences 800 N of air resistance the net force on him is?
Net force = Force of gravity - Force of air resistance = weight - air resistance = mg - 800N.
What is the net force acting on a falling 1-kg rm kg ball if it encounters 2 N rm N of air resistance?
Since gravity attracts the ball downward, and air resistance acts upwards (assuming that it falls straight down), you need to subtract the force of gravity (i.e., the weight) minus the air resistance.
What is the net force acting on a freely falling 1-kg ball if it encounters 2 N of air resistance?
The idea is to calculate the downward force of gravity, and then subtract the air resistance, since it acts in the opposite way. This assumes that the ball falls directly downward.
How does the weight of a falling body compare with the air resistance it encounters before it reaches terminal velocity?
The weight exceeds the force of air resistance, but as the speed increases the air resistance increases, so the net force (weight - air resistance) falls. When the difference becomes zero the acceleration ceases and you have terminal velocity.
What is the net force acting on a 12-N falling object when it encounters 12-N of air resistance?
The net force would be zero, which means the falling object would no longer be accelerating, and would be falling at terminal velocity, which is a constant velocity. Weight is a downward (negative) force and air resistance is an upward (positive) force. Fnet = weight + air resistance = -12N + 12N = 0N
What do you get when the force of air Resistance from the force of gravity?
The net force on a following object
A 20 N falling object encounters 4 N of air pressure what is the magnitude of the net force on the object?
The net force on the falling object is the difference between the gravitational force pulling it down (20 N) and the air resistance force pushing against it (4 N). Therefore, the magnitude of the net force on the object is 16 N.
What is the net force when 10 N encounters 15 N of air resistance?
Since from the description it seems that the forces act in opposite directions, you simply subtract.
An apple falls from a tree. The gravitational force on the apple is 1 N. If air resistance is 0.1 N what is the net force on the apple?
The net force on the apple is 0.9 N. This is calculated by subtracting the force of air resistance (0.1 N) from the gravitational force (1 N).
What is the overall net force of a skydiver?
The overall net force acting on a skydiver is the force of gravity minus air resistance. Initially, as the skydiver falls, gravity is the dominant force causing acceleration. As the skydiver gains speed, air resistance increases, eventually balancing out the force of gravity to reach a terminal velocity where the net force is zero.
