if its in freefall, constant force down = mass (kg) * gravitational acceleration (about 9.8 on earth), so 100 kg body gives 100 * 9.8 = 98 newtons,
subtract your 7 n = 91 n for acceleration .
kiss my butt
The first thing to do is define a positive direction. The right is often defined as being positive, so we shall use that in this problem. We can now define the forces. Let F1= 100lb and F2 = -30lb (It is negative because it is pointing to the left.) Now simply add up the forces: Fnet = F1+F2 Fnet = 100lb + (-30lb) Fnet = 70lb
Bob
guatemala
Sudan: طريق الاربعين (امدرمان بارا الابيض)
The net force would be the difference between the applied force and the air resistance. If the applied force is greater than the air resistance, then the net force would be in the direction of the applied force. If the air resistance is greater than the applied force, then the net force would be in the opposite direction.
You call it a "25N object". Where did it get that label ? It must be because when it's down on land, not freely falling, and you put it on a bathroom scale, the scale reads "25N". When you see that, you know that the mutual forces of gravity in both directions between the object and the Earth are both 25N, and for convenience, you begin to refer to that object as a "25N object". As long as the distance between the object and the center of the Earth remains pretty much the same, so does the gravitational force between them. With that knowledge, we can go on and answer your question. First, the "freely falling" bit. An object plowing through air is not freely falling, because it has to keep pushing air molecules out of its way. Since you call the object a "freely falling" one, we know that there is no air in its path, and there are no springs, weights, bungee cords, people, or rays of mysterious radiation exerting other forces on it. It's just freely falling, somewhere near the surface of the Earth. And since the only force on it is the force of gravity, the magnitude of the force is that old 25N again, acting in the direction that we call "down".
The buoyant force is the weight of the displaced water. That's 15n, and it points upward. That upward force combines with the downward 20n due to gravity. The net force on the object is 5n downward.
The acceleration will be ; a = 1/3 gApplying Newton's 2nd law of motion; F1= m∙g (1)where F1, is the weight of the object (15 N), m is the mass of the object, and g isthe acceleration produced by gravity (g ≈ 9.81 m/s2 ).If the object on a free fall encounters an air resistance of 10 N, the net force actingon the object reduces to 5 N. Then the acceleration experienced by the object willbe given by equation (1); a = F2/m (2)where F2 = 5 N, and also from (1) m = F1/g (3)Eq. (3) on (2) gives; a = (F2/F1) g = (5N/15N) g = 1/3 g ≈ 3.27 m/s2
According to Archimedes principle...An object immersed in water experiences a force equal to the weight of the volume of liquid displaced by it. Here the weight of liquid displaced is 15n. So, the upward buoyant force experienced by that object is 15n.
put your hand there to stop it.
kiss my butt
T = R x F T = 0.5m x 15N T = 7.5 N*m
As they are acting directly against each other, we can simply subtract.The resultant is 15 N to the north.
If you let northward be a positive force and southward be a negative force, you could add the two forces in this manner: +10N + -15N = -5N This gives you not only the magnitude of the net force, but also the direction: 5N southward.
He did 5n per m. Joe's ratio of work to distance is 5:1.
The table provides a support force of 15N to balance the weight of the book, according to Newton's third law. The net force on the book is zero because the support force is equal in magnitude but opposite in direction to the weight of the book, resulting in a balanced force system.