The net ionic equation for the reaction between Pb(NO3)2 and KI is:
Pb2+ (aq) + 2I- (aq) -> PbI2 (s)
This represents the formation of solid lead(II) iodide.
the complete chemical equation for KI AgNO3 and HNO3.the reaction between KI and Ag NO3 can take place you asked a wrong question.AgNO3 + KI = AgI + KNO3Reaction type: double replacement
KI is an ionic compound composed of a metal (potassium) and a non-metal (iodine). It forms an ionic bond where potassium donates an electron to iodine, resulting in the formation of K+ cation and I- anion.
Yes, potassium iodide (KI) is an ionic compound. It is composed of potassium cations (K+) and iodide anions (I-), which are held together by ionic bonds due to the transfer of electrons from potassium to iodine.
The one that is ionic is KI, potassium iodide.
Yes, KI (potassium iodide) is an ionic compound. It is formed between a metal (potassium, K) and a nonmetal (iodine, I) through ionic bonding, where potassium donates its electron to iodine to form an ionic bond.
The net ionic equation for the reaction between aqueous potassium iodide (KI) and aqueous lead(II) nitrate (Pb(NO3)2) is: 2I- (aq) + Pb2+ (aq) → PbI2 (s)
the complete chemical equation for KI AgNO3 and HNO3.the reaction between KI and Ag NO3 can take place you asked a wrong question.AgNO3 + KI = AgI + KNO3Reaction type: double replacement
There is no real "net ionic" equation, as KI is a catalyst that decomposes H2O2. The "slow step" is H2O2 + I- --> OI- + H2O The "fast step" is H2O2 + OI- --> H2O + I- O2 The overall is: 2 H2O2 --> 2H2O + O2
When lead(II) nitrate (Pb(NO₃)₂) is mixed with potassium iodide (KI) in solution, a double displacement reaction occurs, resulting in the formation of lead(II) iodide (PbI₂), which is a precipitate, and potassium nitrate (KNO₃) in solution. The complete ionic equation for this reaction can be written as: [ \text{Pb}^{2+} (aq) + 2 \text{NO}_3^{-} (aq) + 2 \text{K}^{+} (aq) + 2 \text{I}^{-} (aq) \rightarrow \text{PbI}_2 (s) + 2 \text{K}^{+} (aq) + 2 \text{NO}_3^{-} (aq) ] This equation illustrates the dissociation of the soluble ions in solution and the formation of the insoluble lead(II) iodide precipitate.
The chemical equation is: (K+ + I-)(aq) + (Ag+ + [NO3]-)(aq) --> AgI (s) + (K+ + [NO3]-)(aq) or The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
No- KI, Potassium iodide is an ionic compound.
KI is an ionic compound composed of a metal (potassium) and a non-metal (iodine). It forms an ionic bond where potassium donates an electron to iodine, resulting in the formation of K+ cation and I- anion.
Yes, potassium iodide (KI) is an ionic compound. It is composed of potassium cations (K+) and iodide anions (I-), which are held together by ionic bonds due to the transfer of electrons from potassium to iodine.
The one that is ionic is KI, potassium iodide.
The balanced equation for KI + BaS is 2Kl + BaS -> BaI2 + K2S.
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
The formula for potassium iodide is KI.