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Right there on your Periodic Table.
There are fifteen (15) nickels.
It depends on the number of nickels.
Let N be the number of nickels. The value of nickels is 0.05N and the value of dimes is 0.10(2N-12). We can form the equation 0.05N + 0.10(2N-12) = 2.55 and solve for N. After solving, we find that there are 9 nickels.
A 10 dimes and 30 nickels b 21 dimes and 19 nickels c 19 dimes and 21 nickels d20 dimes and 20 nickels
It depends on the size of the box and the number of nickels in it.
20 dimes = 2.00 20 nickels = 1.00 Total = 3.00
There are five nickels (5¢) in a quarter (25¢) so the rule is: 1) Divide the number of nickels by 5 to get the number of quarters 2) The remainder, if any, is the number of nickels left over For example, if you have 17 nickels, 17/5 = 3 rem 2, so that means you have 3 quarters with 2 nickels remaining. To confirm, 17 nickels are worth a total of 85¢ (5 * 17); 3 quarters = 75¢ so 10 cents - i.e. 2 nickels - would be left over.
Pennies: 15 Nickels: 13
Let the number of nickels be ( n ) and the number of dimes be ( d ). According to the problem, we have ( d = 2n - 12 ) and the total value equation ( 0.05n + 0.10d = 2.55 ). Substituting for ( d ) gives ( 0.05n + 0.10(2n - 12) = 2.55 ). Solving this, we find that ( n = 18 ), so there are 18 nickels.
Sue has three nickels.
12 - a half dollar is 50 cents, or 10 nickels; a dime is 10 cents, or 2 nickels.
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