The electron cofiguration of nickel is [Ar]4s1 3d9.
that is only the electron configuration of nickel, a nickel (II) cation would lose the 2 electrons in the 4s and be 1s2 2s2 2p6 3s2 3p6 3d8
The electron configuration for nickel (Ni) is 1s2 2s2 2p6 3s2 3p6 3d8 4s2. This represents the arrangement of electrons in its orbitals following the aufbau principle. The "spdf" notation refers to the distribution of electrons into subshells; for nickel, it would be 1s2 2s2 2p6 3s2 3p6 3d8 4s2.
The electron configuration is incomplete. Assuming that you mean [Ar]4s23dy, here are the possibilities: y=1 Sc y=2 Ti y=3 V y=4 Cr (Actually [Ar]4s13d5) y=5 Mn y=6 Fe y=7 Co y=8 Ni y=9 Cu (Actually [Ar]4s13d10) y=10 Zn Basically the first row of transition metals, since their outermost electron shell is the 3d shell.
The element with 26 electrons and protons is iron (Fe).
26. Nickel has an atomic number of 28, which means that in a normal state, it would have 28 electrons. Ni+2 means that it oxidized by losing two electrons and would thus have only 26 remaining.
no. it doesn't
Ni has 18 core electrons, corresponding to the element Argon, and28 - 18 = 10 valence electrons.The noble gas electron configuration for nickel is [Ar] 4s23d8.
Nickel (Ni) is not a noble gas. Nickel is a transition metal.
Electron configuration is the arrangement of electrons in an atom. There are four blocks in the periodic table: S, P, D, F. Block S is groups 1 and 2. Block P is groups 13-18. Block D is groups 3-12. And block F is the lanthanides and actinides. There are several exceptions, for example He is considered part of S block even though it is over group 18. Here are some examples: He - 1S2 Al - 1S22S22P1 Ni - 1S22S22P63S23P64D8 Shorthand form uses the noble gases (group 18). Whatever element you are using, go to the closest noble gas. For example: Ca - [Ar] 4S2
Zirconium - but it could be simplified to [Kr] 4d2 5s2
Ni, Nickel is NOT a representative element.
The standard model suggests an electron cofiguration for nickel (element number 28)as :[Ar] 4s2 3d8However, relativistic effects make the more stable configuration [Ar] 4s1 3d91s2,2s2,2p6,3s2,3p6,4s2,3d8
that is only the electron configuration of nickel, a nickel (II) cation would lose the 2 electrons in the 4s and be 1s2 2s2 2p6 3s2 3p6 3d8
Only some metals, with a special electron configuration could get magnetic. The most well known metals, that could get magnetic are Iron (Fe), Cobalt (Co) and Nickel (Ni). Also you can find metals in the category of rare earth elements, that could get magnetic. Neon could not get magnetic for two reasons: 1. It is a nonmetal. 2. It has a stable electron configuration.
The electron configuration 4s²3d⁸ corresponds to the element nickel (Ni), which has an atomic number of 28. This configuration indicates that nickel has a total of 28 electrons, with the outermost electrons in the 4s and 3d subshells.
Nickel (Ni) has an atomic number of 28, which means it has 28 electrons. Its electron configuration is [Ar] 3d^8 4s^2. In this configuration, the 3d subshell has 8 electrons, with 2 of them paired and 6 electrons remaining, resulting in 2 unpaired electrons. Therefore, nickel has 2 unpaired electrons.
The electron configuration for nickel (Ni) is 1s2 2s2 2p6 3s2 3p6 3d8 4s2. This represents the arrangement of electrons in its orbitals following the aufbau principle. The "spdf" notation refers to the distribution of electrons into subshells; for nickel, it would be 1s2 2s2 2p6 3s2 3p6 3d8 4s2.