1s22s22p63s23p63d84s2[Ar]3d4s4p
The electron cofiguration of nickel is [Ar]4s1 3d9.
The element with 26 electrons and protons is iron (Fe).
26. Nickel has an atomic number of 28, which means that in a normal state, it would have 28 electrons. Ni+2 means that it oxidized by losing two electrons and would thus have only 26 remaining.
The chemical formula for nickel hydroxide is Ni(OH)2.
that is only the electron configuration of nickel, a nickel (II) cation would lose the 2 electrons in the 4s and be 1s2 2s2 2p6 3s2 3p6 3d8
no. it doesn't
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The electron cofiguration of nickel is [Ar]4s1 3d9.
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LXXIII
Zirconium - but it could be simplified to [Kr] 4d2 5s2
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Nickel(II) is the plus two (+2) oxidation state of nickel (Ni), and we write it Ni(II) or Ni++ when we set it down.
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