(n(n-1) divided by 2 + 1) multiplied by 3) +6
There is no pattern
12, 8
after -9 it is -15 then -21, -27 and the ninth is -36
tn = 3n or 3*3* ... *3 (where there are n threes.)
If by using the formula: nth term = n2+2 the sequence is 3 6 11 18 27 38 51 66.Then it follows that by using the same formula the sequence is III VI XI XVIII XXVII XXXVIII LI LXVI in Roman numerals.
The nth term of the sequence is (n + 1)2 + 2.
The nth term is: n^2 +2 and so the next number will be 38
5n+2
There is no pattern
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.
n3
Willies
2n +29
each time the number increases by 8 and the original number was 3.This means that nth term = 3+(n-1)8ie. the fourth term 27 would be 3 + (4-1)x8 = 3+24 = 27
12, 8
3^n These are powers of 3
the anser is that you are stupid